Ask question

Ask question

All categories

3 years ago

6

Which of the following illustrations show atoms of the same element?

1 answer:

Wittaler [7]3 years ago

6 0

Where are the illustrations?

You might be interested in

Which of the following types of electromagnetic radiation has the most energy?

marysya [2.9K]

You didn't post any choices. A microwave Photon carries more energy than a radio wave photon. An infrared Photon carries more energy than a microwave photon. A visible light Photon carries more energy than an infrared photon. An UltraViolet Photon carries more energy than a visible light photon. An x-ray Photon carries more energy than an UltraViolet photon. A gamma ray Photon carries more energy than an x-ray photon.

4 0

2 years ago

Read 2 more answers

A 0.25 kg book falls off a 2 m shelf on to a 0.5 m chair. What was the change in GPE?

Snowcat [4.5K]

The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.

If we're solving for the change in GPE, then:

∆ $U_{g}$ = mg∆H

<u>Input our given values for m and g:</u>

∆ $U_{g}$ = 0.25 * 9.80 * ∆H

<u>The book falls from 2 meters high to 0.5 meters high, so:</u>

∆ $U_{g}$ = 0.25 * 9.80 * (2.0 - 0.5)

∆ $U_{g}$ = 0.25 * 9.80 * 1.5

∆ $U_{g}$ = 3.675 (J)

<u>Adjust for significant figures:</u>

∆ $U_{g}$ = 3.7 (J)

The change in gravitational potential energy was 3.7 (J)

If you have any questions on anything I did to get to the answer, just ask!

- breezyツ

6 0

2 years ago

A ball is thrown vertically upward with a speed of 19.0 m/s. (a) How high does it rise? m (b) How long does it take to reach its

Arte-miy333 [17]

Answer with Explanation:

We are given that

Initial speed= $u=19 m/s$

a. $g=9.8m/s^2$

Final velocity of ball= $v=0$

$v=u-gt$

g is negative because the ball is going against to gravity.

$0=19-9.8t$

$9.8t=19$

$t=\frac{19}{9.8}=1.94 s$

$s=ut-\frac{1}{2}gt^2$

Using the formula

$s=19(1.94)-\frac{1}{2}(9.8)(1.94)^2$

$s=18.4 m$

a.The ball rise upto height 18.4 m

b.It take 1.94 s to reach its highest point.

c.Initial velocity=0,s=18.4 m

$s=ut+\frac{1}{2}gt^2$

$18.4=0(t)+\frac{1}{2}(9.8)t^2$

$18.4=4.9t^2$

$t^2=\frac{18.4}{4.9}$

$t=\sqrt{\frac{18.4}{4.9}}$

$t=1.94 s$

$v=u+gt$

Using the formula

$v=0+9.8(1.94)=19 m/s$

7 0

3 years ago

Read 2 more answers

I need help in this pls i really need a answer

IrinaK [193]

Answer:

In terms of distance, average speed is 20 km/h

In terms of displacement, average speed is 0 km/h.

Explanation:

Total distance:

$= (40.0 - 10.0) + (20.0 - 10.0) + (40.0 - 20.0) \\ = 30.0 + 10.0 + 20.0 \\ = 60.0 \: km$

Total time is 3.0 hours

but:

$average \: speed = \frac{total \: distance}{total \: time} \\$

In terms of distance.

substitute:

$average \: speed = \frac{60.0}{3.0} \\ \\ = 20 \: {kmh}^{ - 1}$

$displacement = ( - 30.0) + 10 .0+ 20.0 \\ = 0$

In terms of displacement:

$speed = \frac{0}{3} \\ \\ = 0 \: {kmh}^{ - 1}$

3 0

3 years ago

Suppose the current in a conductor decreases exponentially with time according to the equation I(t) = I0e-t/τ, where I0 is the i

ELEN [110]

Answer:

Pls see attached file

Explanation:

5 0

3 years ago