Answer:
Explanation:
We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .
f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .
f will be lowest when v₀ is highest .
velocity of observer is highest when he is at the equilibrium position or at middle point .
So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .
Explanation:
Speed or velocity (V) = 35 m/s
Kinetic energy (K. E) = 1500 Joule
mass (m) = ?
We know
K.E = 1/2 * m * v²
1500 = 1/2 * m * 35²
1500 * 2 = 1225m
m = 3000 / 1225
m = 2.45 kg
The mass of the object is 2.45 kg
Hope it will help :)
Answer:
The radius of the earth is 6,371 km.
The average Earth-Sun distance is 152.09 million km
How many Earths would fit between Earth and the Sun if they are separated by their average distance? Approximately 11,936 Earths.
I didn't really understand the last part, but if you don't get a better answer please mark me as brainliest.
three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650
The pressure exerted on the table due to the book is 200 N/m².
The given parameters;
- <em>mass of the book, m = 400 g = 0.4 kg</em>
- <em>dimension of the table, = 0.10m x 0.20 m.</em>
- <em>gravitational field strength g = 10 N/kg.</em>
The area of the table is calculated as follows;
A = 0.1 x 0.2 = 0.02 m²
The pressure exerted on the table due to the book is calculated as follows;
where;
- <em>F is the force of the book due to its weight</em>
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Thus, the pressure exerted on the table due to the book is 200 N/m².
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