1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marshall27 [118]
3 years ago
6

A pendulum is transported from sea-level, where the acceleration due to gravity g is 9.80 m/s2, to the bottom of Death Valley. A

t this location, the period of the pendulum is decreased by 3.00%. What is the value of g in Death Valley
Physics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer: the value of g in Death Valley is 10.417 m/s²

Explanation:

Given that;

acceleration due to gravity at the point is g = 9.8 m/s²

Lets say the acceleration due to gravity at the bottom of Death valley is g'

as the period of the pendulum is decreased by 3.00%

T' = 0.97 T  

T is the period of the pendulum at sea level  and T' is the period of the pendulum at bottom of Death valley

therefore from the relation

T = 2π√(l/g)

g'/g = T²/T'²

g' = (T²/ (0.97T)²)g

g' = 1.063g

g' = 10.417 m/s²

therefore the value of g in Death Valley is 10.417 m/s²

You might be interested in
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

T = 2 \pi \sqrt{\frac{m}{k} } \\

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

Hence the force constant of the spring is 17.71N/m

4 0
3 years ago
Blocks A (mass 2.00 kg) and B (mass 10.00 kg, to the right of A) move on a frictionless, horizontal surface. Initially, block B
olga2289 [7]

Answer:dont care

Explanation:

5 0
3 years ago
Part of understanding the physical effects on Mars, we must understand
Ber [7]

Answer:

so easy add the subtract then multiplay the add

Explanation:

8 0
3 years ago
El aspa de un ventilador de 0.30 m de diametro gira 1200 rev/min. calcule la rapidez tangencial.
Keith_Richards [23]

Answer:

v = 18.84 m/s

Explanation:

Let the question says,"The blade of a 0.30 m diameter fan rotates 1200 rev / min. calculate the tangential speed."

It is given that,

Diameter of a blade of fan is 0.3 m

Angular velocity of the fan is 1200 rev/min or 125.66 rad/s

We need to find the tangential speed of the fan. The relation is given by :

v=r\omega

r is radius of fan

v=0.15\times 125.66 \\\\v=18.84\ m/s

So, the tangential velocity is 18.84 m/s.

4 0
3 years ago
The angular momentum of a flywheel having a rotational inertia of 0.200 kg·m2 about its central axis decreases from 3.80 to 0.40
babymother [125]

Explanation:

Below is an attachment containing the solution

3 0
3 years ago
Other questions:
  • A rock climber weighs 550N and is carrying a backpack that weighs 50N. How much total work has been done after she climbs 12M
    5·1 answer
  • A calorimeter directly measures ______ in order to calculate ______. (1 point)
    8·2 answers
  • At the surface of the earth, there is an approximate average solar flux of 0.75 kW/m2. A family wishes to construct a solar ener
    14·1 answer
  • Why are noise considerations important in optical fiber communications? 3. Describe the principle of "population inversion".
    13·1 answer
  • Jan ran 4 miles north in 28 minutes. What was Jan's average velocity?
    8·1 answer
  • Describe how sound waves are produced by the drum and then heard.
    11·1 answer
  • M = 15 kg, a = 2 m/s2, F =
    11·1 answer
  • A disk-shaped space station 125 m in diameter spins at a constant angular velocity. If the acceleration of a point on the rim of
    5·1 answer
  • A 1.0kg cart moving right at 5.0 m/s on a frictionless track collides and
    9·1 answer
  • Indicate all ways in which the graph used in question 4 would change if the Normal Force applied to the object was increased. Be
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!