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3 years ago

How can you define a solution to an equation?

1 answer:

8 0

A solution is a value or a collection of values.. when substituted for the unknowns, the equation become an equality.
Example : x + 2 = 7
When we out the 5 in place of x we get: 5 + 2 = 2

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The velocity of an object is positive and steadily increasing. Which of the following graphs represents how the acceleration of

stiv31 [10]

If an object's velocity is steadily increasing it means that the acceleration is constant at a certain value.

Choice A shows an acceleration of zero which would only be true if the object was not moving or if its velocity was not changing.

Choice B gives us a graph showing acceleration increasing over time and is therefore incorrect.

Choice C is correct because the acceleration is constant. Steadily increasing tells us that the acceleration is fixed at a certain value.

Choice D is incorrect an represents a constant negative acceleration. This would be the case if the object was steadily decreasing in velocity.

4 0

3 years ago

At the top of a looped section of roller coaster track, the car and rider are completely upside down. Engineers calculated that

Pie

Answer:

m v^2 / R = m g where gravitational force provides centripetal force

R = v^2 / g = 14.3^2 m/s / 9.8 m/s^2 = 20.9 m

7 0

3 years ago

Explain what happens to the pitch of a cell phone ring when the wavelength of a sound wave increases

max2010maxim [7]

You get a more low sound.

Conversely, when the wavelength becomes shorter you get a more treble sound.

;-)

4 0

3 years ago

Read 2 more answers

A parallel-plate capacitor has a voltage of 391 v applied across its plates, then the voltage source is removed. what is the vol

andrezito [222]

When the capacitor is connected to the voltage, a charge Q is stored on its plates. Calling $C_0$ the capacitance of the capacitor in air, the charge Q, the capacitance $C_0$ and the voltage ( $V_0=391 V$ ) are related by

$C_0 =\frac{Q}{V_0}$ (1)

when the source is disconnected the charge Q remains on the capacitor.

When the space between the plates is filled with mica, the capacitance of the capacitor increases by a factor 5.4 (the permittivity of the mica compared to that of the air):

$C=k C_0 = 5.4 C_0$

this is the new capacitance. Since the charge Q on the plates remains the same, by using eq. (1) we can find the new voltage across the capacitor:

$V=\frac{Q}{C}=\frac{Q}{5.4 C_0}$

And since $Q=C_0 V_0$ , substituting into the previous equation, we find:

$V=\frac{C_0 V_0}{5.4 C_0}=\frac{V_0}{5.4}=\frac{391 V}{5.4}=72.4 V$

7 0

3 years ago

what are three activities in your everyday life that involve electromagnetic energy? and explain what type of electromagnetic en

mihalych1998 [28]

1). While I'm driving the car, I keep my eyes pointed out the front window,

so that LIGHT WAVES coming straight in through the front window get into

them. Using this process, I'm able to SEE what's in front of me, so that I don't

drive straight into it.

2). Also while I'm driving the car, I usually have the radio on, and I tune it

to a frequency where the RADIO WAVES that it responds to are being

modulated by people who are either talking or else playing classical music.

3). Before I leave the house on most days, I take a small container of

frozen Irish oatmeal out of the freezer, and I load it into the big box

above the stove, where MICROWAVE ENERGY thaws it, and warms

it to a nice eating temperature.

3A). When I arrive at my job, I usually do things that are also associated

in some way with MICROWAVE energy, since I work as a microwave

system design engineer. Most of the time it's just paperwork, but there

ARE times when I work with an actual radio that's either generating or

detecting real microwave energy, and either sending it up to, or receiving

it down from, a big dish antenna on a radio tower. Those are the days that

I like the best.

8 0

3 years ago