A satellites are placed in a circular orbit that is 2.44 × 107 m above the surface of the earth. What is the magnitude of the ac
1 answer:
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Answer:
31.8 m in the positive x-direction
Explanation:
Here we have an example of multiplication of a vector by a scalar.
In order to perform this operation, we have to:
- multiply the magnitude of the vector by the scalar
- reverse the direction of the vector if the scalar is a negative number
In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:
- The magnitude is obtained by calculating the product
- The direction is reversed, because the scalar is -3.7, so the new vector will point in the positive x-direction
So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.
Answer:
Its state is in uniformly accelerated motion
Explanation:
When an object is acted upon the force of gravity only, we said that the object is in free fall.
According to Newton's second law of motion:
where F is the net force on an object, m is its mass, a its acceleration, when the net force on an object (F) is non-zero, than the object accelerates (because a is non-zero), so the object is in accelerated motion.
In case of free fall, the rate of acceleration of the object is equal to , the acceleration due to gravity, and it is constant. So, the object is moving by uniformly accelerated motion.