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Elden [556K]
3 years ago
12

A satellites are placed in a circular orbit that is 2.44 × 107 m above the surface of the earth. What is the magnitude of the ac

celeration due to gravity at this distance?
Physics
1 answer:
Vikki [24]3 years ago
7 0
2.440
X 107. The magnitude
------------ Is 261.080 plz
17.080. Make the
00.000. Brainliest
244.000
----------------
261.080
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A group of bike riders took a 4 hour trip. During the first 3 hours, they traveled a total of 50 km, but
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Answer:

15km/hr

Explanation:

The average speed for the entire trip is the sum of the total distance traveled divided by the total time of the trip.

Total time  = 4hr

distance for the first 3hrs  = 50km

distance for the last 1hr  = 10km

  Total distance  = 50km + 10km  = 60km

Now;

  Average speed  = \frac{total distance }{time taken}  

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 Average speed  = \frac{60km}{4hr}   = 15km/hr

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3 years ago
Raw sewage is raised vertically by 5.49m in the amountof
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Answer:

          P = 1235.7646 W

Explanation:

Given data:

height of raised sewage = 5.49 m

rate of sewage =1.89*10^6 lt/day

density of sewage = 1.050 kg/m^3

power is written as

P = \frac{work}{time}

work  = m g h

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  h -height

mass lifted per day = ( 1.89*10^6)(1.050)

                              = 1984500 kg

time = 24 hours* 3600 seconds per hour

powerP = \frac{( 1984500)(9.8)( 5.49)}{(24)(3600)}

          P = 1235.7646 W

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Passes the the law then through the people where it is followed
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C + H2 ----------&gt; CH4
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yes

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