Question

HELP PLS

Answer 1

Answer:

The volume of the gas decreases 140 times.

Explanation:

The equation of state of the ideal gas is described below:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure.

$V$ - Volume.

$n$ - Molar quantity.

$R_{u}$ - Ideal gas constant.

$T$ - Temperature.

From this formula we construct the following relationship:

$\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}$ (2)

Where:

$P_{1}$, $P_{2}$ - Initial and final pressure.

$V_{1}$, $V_{2}$ - Initial and final volume.

$T_{1}$, $T_{2}$ - Initial and final temperature.

$\frac{V_{2}}{V_{1}} = \frac{\frac{T_{2}}{T_{1}} }{\frac{P_{2}}{P_{1}} }$

If we know that $\frac{T_{2}}{T_{1}} = \frac{1}{14}$ and $\frac{P_{2}}{P_{1}} = 10$, then the change in the volume of the gas is:

$\frac{V_{2}}{V_{1}} = \frac{\frac{1}{14} }{10}$

$\frac{V_{2}}{V_{1}} = \frac{1}{140}$

The volume of the gas decreases 140 times.