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otez555 [7]
3 years ago
12

ace taxi charges $3 a flat fee plus 1.50 per mile driven. browns cab charges $5.50 flat fee plus $1.25 per mile. How many miles

must go in order for the cost of the two taxicab services to equal each other? How much money will it cost? I need help on this problem so please help me :(
Mathematics
1 answer:
suter [353]3 years ago
7 0
Set the two equations equal to each other and solve for X
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<img src="https://tex.z-dn.net/?f=5%5Cfrac%7B1%7D%7B4%7D%20%20%2B%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%201%20%20%5Cfrac%7B5%7D
kobusy [5.1K]

Answer:

7 5/12

Step-by-step explanation:

5 1/4 + 3/4 + 1 5/12

We can add the first two terms

5 1/4 + 3/4

5 4/4

6

6 + 1 5/12

7 5/12

4 0
2 years ago
Bethany has 28 oatmeal cookies and 36 peanut butter cookies to pack. each bag will contain only one kind of cookie,and every bag
m_a_m_a [10]
252 bags will be there.
it is the LCM of 28 and 36
8 0
2 years ago
Use the Distributive Property to simplify the expression.<br><br> 10(b−6) =
Harrizon [31]
10b - 60
explanation: distribute
8 0
2 years ago
Factor (Reverse Distribute): 4+6
Allisa [31]
4+6=10 if you have 4 apples and you add 6 apples you are left with 10 apples
7 0
3 years ago
A freshly inoculated bacterial culture of Streptococcus contains 100 cells. When the culture is checked 60 minutes later, it is
Luba_88 [7]

Answer:

P(t) = 100e^{0.0251t}

The doubling time is of 27.65 minutes.

Step-by-step explanation:

Exponential equation of growth:

The exponential equation for population growth is given by:

P(t) = P(0)e^{kt}

In which P(0) is the initial value and k is the growth rate.

A freshly inoculated bacterial culture of Streptococcus contains 100 cells.

This means that P(0) = 100. So

P(t) = 100e^{kt}

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.

This means that P(60) = 450, and we use this to find k. So

450 = 100e^{60k}

e^{60k} = 4.5

\ln{e^{60k}} = \ln{4.5}

60k = \ln{4.5}

k = \frac{\ln{4.5}}{60}

k = 0.0251

So

P(t) = 100e^{0.0251t}

Doubling time:

This is t for which P(t) = 2P(0) = 200. So

200 = 100e^{0.0251t}

e^{0.0251t} = 2

\ln{e^{0.0251t}} = \ln{2}

0.0251t = \ln{2}

t = \frac{\ln{2}}{0.0251}

t = 27.65

The doubling time is of 27.65 minutes.

7 0
3 years ago
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