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klemol [59]
3 years ago
15

The most common character encoding in use is

SAT
1 answer:
Advocard [28]3 years ago
8 0
UTF-8 is most commonly used in encoding in today’s computers
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4. Which of the following statements is correct?
Leni [432]

A, four way switches have the word" on" engravedon their hand<em><u>l</u></em><em><u>e</u></em><em><u>s</u></em>

6 0
3 years ago
Read 2 more answers
Precipitation of ribosomes and RNA
zimovet [89]

Precipitation of ribosomes and RNA is "None of the options are correct. So Precipitation of ribosomes and RNA does not produce any of the inclusions listed.

<h3>What is Precipitation of ribosomes?</h3>

Heinz bodies are aggregates of denatured hemoglobin that form in red blood cells due to oxidative stress. They are seen in conditions such as glucose-6-phosphate dehydrogenase deficiency, thalassemia, and some drugs.

Howell-Jolly bodies are remnants of nuclear DNA that are normally removed from red blood cells by the spleen. They are seen in conditions such as asplenia, hyposplenia, megaloblastic anemia, and hemolytic anemia.

Therefore, Auer rods are cytoplasmic inclusions that contain granules of myeloperoxidase and other enzymes. They are seen in malignant white blood cells, especially in acute myeloid leukemia."

Learn more about ribosomes from

brainly.com/question/8773679

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4 0
1 year ago
If x= 7/9 then which one of the following is not greater than x
vivado [14]

Answer:

b

Explanation:

a. (x-2)/(x-1) =(7/9-2)/(7/9-1)

=<u>-</u><u>1</u><u>1</u><u>/</u><u>9</u><u> </u> =11/2 >x

-2/9

b. <u>7</u><u>/</u><u>9</u><u>+</u><u>1</u> =<u>1</u><u>6</u><u>/</u><u>9</u> =-8<x

7/9-1 -2/9

c. <u>1</u><u> </u><u> </u> =9/7 >x

7/9

d. <u>(7/9+1)</u><u> </u> =<u>16/9 </u><u>=</u> 16/7 >x

7/9 7/9

8 0
3 years ago
Read 2 more answers
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri
xxTIMURxx [149]

The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

<h3>What is the standard error of the distribution?</h3>

The standard error of the distribution is calculated as follows:

  • Standard error = standard deviation/√N

where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

  • 68% of the data lies within one standard deviation
  • 95% percent within two standard deviations, and
  • 99.7% within three standard deviations from the mean.

Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

Learn more about standard error at: brainly.com/question/14467769

#SPJ1

6 0
1 year ago
For the sake of rhetorical effect, the writer wants to maintain the pattern of repeating words derived from the same root. Which
Nastasia [14]

Answer: I Might tell you what to do

Explanation:

5 0
3 years ago
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