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hoa [83]
3 years ago
14

I dont know what I'm doing! could you help me​

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

c = 24.34

Step-by-step explanation:

Here, we can use the cosine rule

Generally, we have this as:

a^2 = b^2 + c^2 - 2bcCos A

12^2 = 14^2 + c^2 - 2(14)Cos 19

144 = 196 + c^2 - 26.5c

c^2 - 26.5c + 196-144 = 0

c^2 - 26.5c + 52 = 0

We can use the quadratic formula here

and that is;

{-(-26.5) ± √(-26.5)^2 -4(1)(52)}/2

(26.5 + 22.23)/2 or (26.5 - 22.23)/2

24.37 or 2.135

By approximation c = 24.34 will be correct

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Aleks04 [339]

The answer is none of the lines intersect each other, because they are at the same slope, and they do not have a different slope for the lines to be intersected.

3 0
3 years ago
What is Circumference= 21.98 in. <br>​
Cerrena [4.2K]

Answer:

38.45

Step-by-step explanation:

5 0
3 years ago
To solve a polynomial inequality, we factor the polynomial
Pavel [41]

Answer:

To solve a polynomial inequality, we factor the polynomial into irreducible factors and find all the real _zeros_ polynomial. Then we find the intervals determined by the real _zeros and use test points in each interval to find the_ sign of the polynomial on that interval.

If P(x) = x(x+2)(x-1)

And P(x) ≥ 0

We see that P(x) ≥ 0 on the intervals (-2, 0) and (1, ∞).

Step-by-step explanation:

The complete question is attached to this solution

To solve inequality of a polynomial, we first obtain the solutions of the polynomial. The solutions of the polynomial are called the zeros of the polynomial.

If P(x) = x(x+2)(x-1)

The solutions of this polynomial, that is the zeros of this polynomial are 0, -2 and 1.

To now solve the inequality that arises when

P(x) ≥ 0

We redraw the table and examine the intervals

The intervals to be examined as obtained from the zeros include (-∞, -2), (-2, 0), (0, 1) and (1, ∞)

Sign of | x<-2 | -2<x<0 | 0<x<1 | x>1

x               | -ve | -ve | +ve | +ve

(x + 2)       | -ve | +ve | +ve | +ve

(x - 1)         | -ve | -ve | -ve | +ve

x(x+2)(x-1) | -ve | +ve | -ve | +ve

The intervals that satisfy the polynomial inequality P(x) = x(x+2)(x-1) ≥ 0 include

(-2, 0) and (1, ∞)

Hope this Helps!!!

6 0
3 years ago
For 250 points and brainiest......
igor_vitrenko [27]

Answer:

1.) -7,-5,0

2.)-3,-2,10

3.)-18.5,-12.5,18

4.)-24.5-20,26

Step-by-step explanation:

6 0
3 years ago
(4, 3) is a solution to the following system of equations:
sasho [114]
The first answer is true and the second answer is true as for how this actually is just plug in the numbers

x=4, y=3

2(4)=8 8+3=11

4-1=3
4 0
4 years ago
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