The second step is wrong. What should've been done is to find greatest common factor (gcf) of 1/6 and -2. This is because you cannont add together a number with a variable to a number without a variable. So get the variable by itself by subtracting 1/6 from both sides.
1/5x + 1/6 = -2
___— 1/6_— 1/6
____________
Turn -2 into a fraction and find the gcf of -2 and 6:
1/5x + 1/6 = -2
___— 1/6_— 1/6
____________
1/5x = -2/1 — 1/6 ——> 1/5x = -12/6 — 1/6
1/5x = -13/6
Then divide each side by 1/5 to get the variable by itself; remeber: when dividing a fraction by a fraction, you multiply by the reciprocal.
5/1 • 1/5x = -13/6 • 5/1
x = 65/6
Then, simplify
65/6} 10.83 or 10 83/100
Answer:
12 Pints
Step-by-step explanation:
There are 8 pints (pt) in 1 gallon (gal). This means that 1 pint equals 1/8 gallon.
1.5 x 8
=12
I think it is A but make sure with someone else
This has both a horizontal and a vertical asymptote. There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator. If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0. But we also have a vertical asymptote, which occurs where the denominator = 0. We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.
The roots: this is when y=0, so in yours there are 2 roots. Just look at the x value when y=0 and that is your roots.
Y intercept- this is when x=0, so just look at the y value below x=0 and that is the y intercept. Note the answer will probably be in the form (0,_)
Vertex=do you see a pattern? Well the vertest would be the highest or lowest point of the quadratic equation. Your vertex would be (5,-9) because just look at x=4 and x=6, bit of the y values are -8 and when you look at x=3 and x=7 they are also the same because this is a quadratic equation.
Max or min: yours is a minimum because (5,-9) is the lowest point. Every value left and right of this are higher up the graph, so this would be a minimum.
*something that will help you see this all more clearly is if you graphed this or put it into Desmos to see the vertex etc.
