Step-by-step explanation:
A.
![(6^2)^x=1\\\\36^x=1\\\\36^x=36^0\Rightarrow x=0](https://tex.z-dn.net/?f=%286%5E2%29%5Ex%3D1%5C%5C%5C%5C36%5Ex%3D1%5C%5C%5C%5C36%5Ex%3D36%5E0%5CRightarrow%20x%3D0)
Every number to the power of 0 gives us 1
![a^0=1\ \text{for}\ a\in\mathbb{R}](https://tex.z-dn.net/?f=a%5E0%3D1%5C%20%5Ctext%7Bfor%7D%5C%20a%5Cin%5Cmathbb%7BR%7D)
B.
![(6^0)^x=1\\\\1^x=1\\\\x\in\mathbb{R}](https://tex.z-dn.net/?f=%286%5E0%29%5Ex%3D1%5C%5C%5C%5C1%5Ex%3D1%5C%5C%5C%5Cx%5Cin%5Cmathbb%7BR%7D)
1 to the any power gives us 1.
![1^n=1\ \text{for}\ n\in\mathbb{R}](https://tex.z-dn.net/?f=1%5En%3D1%5C%20%5Ctext%7Bfor%7D%5C%20n%5Cin%5Cmathbb%7BR%7D)
Answer:
Obtuse isosceles
Step-by-step explanation:
Two sides are the same length, so we know this is an isosceles triangle.
To determine if it's acute, right, or obtuse, we can compare it to a right triangle using Pythagorean Theorem:
c² = a² + b²
c² = 3² + 3²
c² = 18
c = √18
So if this were a right triangle, c would be √18, which is somewhere between 4 and 5.
Since the long side is greater than √18, we know this must be an obtuse triangle.
So this is an obtuse isosceles.
Answer:
3, 8, 13, 18, 23
Step-by-step explanation:
The recursive definition tells you the first term is 3, and that each successive term is 5 more than the one before. 5 terms are ...
3, 8, 13, 18, 23
<span>$1,337.03 is your answer </span><span />