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3 years ago

Which property of equality was used to solve this equation?

Mathematics

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

D. Division property of equality.

Step-by-step explanation:

$- 5x = 4 \: \: \: \frac{ - 5x}{ - 5} = \frac{4}{ - 5} \: \: \: \: x = \frac{ - 4}{5}$

We divided the terms on both sides by -5.

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15 POINTS+BRAINLIEST (Hurry now) A train goes past you in 10 seconds and goes past a 100 meter long bridge in 30 seconds. What i

Dmitry_Shevchenko [17]

Answer:

speed=3.33m/s

Step-by-step explanation:

speed= distance÷time

3.33 m/s

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3 years ago

3 4/7 minus 2 1/5 by rounding to the nearest half

mylen [45]

Answer:

$1 \frac{13}{35}$

Step-by-step explanation:

$3 \frac{4}{7} - 2 \frac{1}{5}$

you can solve for the fractions first, but you have to give them a common denominator

$\frac{20}{35}- \frac{7}{35}$

$= \frac{13}{35}$ which is in simplest form

then solve for the whole numbers

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therefore, the answer is $1 \frac{13}{35}$

6 0

3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

PLEASE ANSWER QUICK!!

Citrus2011 [14]

Answer:

A) B is greater

B) when C = 21, A = 5 and B = 15

C) A must be 0, 5, or 12 for C to be greater than B

Step-by-step explanation:

A) when a = -3, c = -20 and b = 4(-3)-5 so B = -17

B) when c = 21, a = 5 and b = 4(5)-5 so B = 15

C) C is greater than B when a = 0, 5, and 12

when a = 0, b = 4(0)-5 or -5

when a = 5, b = 4(5)-5 or 15

when a = 12, b = 4(12)-5 or 43

3 0

2 years ago

Which expression use the associative property to make it easier to evaluate 20 (3/5 × 6)

Marizza181 [45]

Answer:

Step-by-step explanation:

7 0

3 years ago

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