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Maru [420]
3 years ago
14

A set of 36 cards is numbered with the positive integers from 1 to 36. If the cards are shuffled and one is chosen at random, wh

at is the probability that the number on the card is a multiple of both 4 and 6?
Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

1/12.

Step-by-step explanation:

The numbers divisible by 6 are 6, 12, 18, 24, 30 and 36.

Of these  12, 24 and 36 are also divisible by 4.

So the required probability is 3/36

= 1/12.

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What is the factorization of x2+ 10x+21
Marta_Voda [28]

Answer:

(x+7) (x+3)

Step-by-step explanation:

x times x equals x2

3x + 7x = 10x

7 x 3 = 21

(x+7) (x+3)


7 0
3 years ago
What are the coordinates of the terminal point for 0=330
Ira Lisetskai [31]

Answer: Option C.

Step-by-step explanation:

The coordinates (x,y) of a terminal point for an angle θ are:

x = cos(θ) and y = sin(θ).

In this case, we have θ = 330°.

Then we have:

x = cos(330°) = 0.866 = (√3)/2

y = sin(330°) = -0.5 = -1/2

then the coordinates of the terminal point are ((√3)/2, -1/2)

Then the correct option is c.

3 0
3 years ago
Solve the equation for y. Then graph the equation. 5x – 4y = 12
iVinArrow [24]
-3+ \frac{5}{4}x
6 0
3 years ago
Whats the lateeal area of length 18, width 13,and 6 hieght
Wewaii [24]
Idk tell someone else
5 0
3 years ago
What proportion of the first 10,000 natural numbers contain a 3
Sergeeva-Olga [200]
In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n -> 10^n - 9^n  (contain a 3).




So for 10^4 -> 10^4 - 9^4 = 10.000 - 6.561 = 3.439 


<u>The answer is 3.439 numbers contain a 3 in the first 10.000</u>

3 0
3 years ago
Read 2 more answers
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