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Liula [17]
2 years ago
9

What is TeO3 compound name​

Physics
2 answers:
arlik [135]2 years ago
8 0

tellurium oxide

is the answer

remember

use the chemical name for the first element then for the second element

use the chemical name and add 'ide'

like oxygen and then oxide

Stolb23 [73]2 years ago
4 0

Tellurium trioxide

Hope this helps you!!!

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A ball is dropped off the side of a bridge.<br> After 1.55 s, how far has it fallen?
KengaRu [80]

Answer:11.7 meters

Explanation: Gravitational acceleration (g)

9.8 m/s²

Initial velocity (v₀)

0 ft/s

Height (h)

11.77225 m

Time of fall (t)

1.55 sec

Velocity (v)

15.19 m/s

6 0
3 years ago
HELP HELP HELP HELP HELPPPPPPPPPPP
Firdavs [7]

Initial velocity (u) = 2 m/s

Acceleration (a) = 10 m/s^2

Time taken (t) = 4 s

Let the final velocity be v.

By using the equation,

v = u + at, we get

or, v = 2 + 10 × 4

or, v = 2 + 40

or, v = 42

The final velocity is 42 m/s.

5 0
2 years ago
Read 2 more answers
A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa
bearhunter [10]

Explanation:

Formula which holds true for a leans with radii R_{1} and R_{2} and index refraction n is given as follows.

          \frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

Since, the lens is immersed in liquid with index of refraction n_{1}. Therefore, focal length obeys the following.  

            \frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]  

             \frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

and,       \frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}

or,          f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}

              f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}

                          = 32.4 cm

Using thin lens equation, we will find the focal length as follows.

             \frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}

Hence, image distance can be calculated as follows.

       \frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}

              s_{i} = \frac{fs_{o}}{s_{o} - f}

             s_{i} = \frac{32.4 \times 100}{100 - 32.4}

                       = 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0
3 years ago
What's the time it takes a car to attain the speed of 30 m/s when accelerating from rest at 2 m/s (squared)
bekas [8.4K]
I guess a idk lol good luck tho
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How does beam spreading affect the temperature on earth and the seasons
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Get to school and learn boi
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