Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V
C1= 3×10^-6 F
V1= 480v
C2= 4×10^-6 F
V2= 500v
(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V
Simplifying the above, we get:
( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.
Further simplified as:
3440 × 10^-6 = 7 × 10^-6 × V
Making V the subject
V = 491.43volts
Therefore the potential difference across each capacitor is 491.43v
Answer:
It's B.
Explanation:
Found answer off Quizlet.
Answer:
0.3 N
Explanation:
mass of cork = 0.01 kg, density of cork = 250 kg/m^3
density of water = 1000 kg/m^3, g = 10 m/s^2
Tension in the rope = Buoyant force acting on the cork - Weight of the cork
Buoyant force = volume of cork x density of water x g
= mass x density of water x g / density of cork
= 0.01 x 1000 x 10 / 250 = 0.4 N
Weight of cork = mass of cork x g = 0.01 x 10 = 0.1 N
Thus, the tension in the rope = 0.4 - 0.1 = 0.3 N
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In a Decentralized organization, all different managers from different divisions have the authority to make decision
