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MArishka [77]
3 years ago
15

Write down the name of each of these shapes :( ​

Mathematics
2 answers:
Arturiano [62]3 years ago
7 0

Answer:

A): Right triangle (Right angle)

B): Scalene triangle (No equal angles or side lengths)

mamaluj [8]3 years ago
5 0
1. Right triangle /90 degrees
2. Scalene triangle
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n200080 [17]

Answer:

18 r2

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2 years ago
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What is the image point (-2,-7) after a translation right 4 units and down 2 units
xenn [34]

Answer:

(2,-9)

Step-by-step explanation:

-2+4=2

-7-2=-9

down=negative

right=positive

left=negative

up=positive

7 0
3 years ago
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a sphere of radius 5 cm is melted down and made into a solid cube. Find the length of a side of the cube.​
Amanda [17]

Answer:

the volume of sphere will be equal to that of the volume of cube as change in shape doesn't effect the volume.

using,

Volume of sphere = volume of cube.

= a^3

Step-by-step explanation:

5 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
I need help with this 1 problem on my homework
Andru [333]

Step-by-step explanation:

10-5y=3x

1. add 10 to both sides

-5y=3x+10

2. divide everything by -5

y=-3/5x-2

3. your point would start at -2 on the y axis and you would go down 3 and over 5 to get to the next point

4 0
3 years ago
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