Ask question

Ask question

All categories

3 years ago

15

During the drying cycle, clothes soaked in liquid PERC at 300 K at 1 atm are tumbled in a stream of warm air at 330 K at 1 atm t

hat circulates through the basket causing the liquid to evaporate. How do the kinetic energy (K) and potential energy (Ep) of PERC molecules in the liquid change during the evaporation?
A. K decreases; Ep increases.
B. K increases; Ep increases.
C. K remains constant; Ep decreases.
D. K remains constant; Ep increases.

1 answer:

djyliett [7]3 years ago

6 0

The answer is option A

You might be interested in

A 1.897g sample of Mg(HCO3)2 was heated and decomposed. When the sample

svlad2 [7]

1.5 % is the percent yield in the reaction.

Explanation:

Given that:

original mass of the sample used in reaction = 1.897 grams

product formed after decomposition = 1.071 grams

The reaction for the decomposition:

Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)

It says that 1 mole of Mg(HCO3)2 yielded 1 mole of MgCO2 on decomposition

68.31 grams/mole or 68.31 grams of MgCO2 is formed

percent yield = $\frac{actual yield}{theoretical yield}$ x 100

putting the values in the equation:

percent yield = $\frac{1.071}{68.31}$

= 0.015 x100

PERCENT YIELD = 1.5 %

8 0

3 years ago

An atom of iron has the atomic number 26 and a mass number of 56. how many protons plus neutrons are in the nucleus?

mojhsa [17]

<span>iron has 26 protons and 30 neutrons are in the nucleus</span>

4 0

3 years ago

Read 2 more answers

Several constructive processes helped build mountains on Earth. All BUT one of these is a way mountains can be built. That is A)

Naddik [55]

It is landslides i got it right on the test

7 0

3 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

Brut [27]

<u>Answer:</u> The smallest temperature change is shown by water.

<u>Explanation:</u>

To calculate the heat absorbed or released, we use the equation:

$q=mC\times \Delta T$ ......(1)

where,

q = heat absorbed = 200.0 J

m = mass of the substance

C = specific heat of substance

$\Delta T$ = change in temperature

As, the same amount of heat is getting absorbed in all the cases. So, the change in temperature will depend on the product of mass and specific heat.

For the given options:

<u>Option a:</u> 50.0 g Fe, $C_{Fe}=0.449J/g^oC$

We are given:

$m=50.0g\\C_{Fe}=0.449J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 0.449J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 0.449}=8.99^oC$

Change in temperature = 8.99°C

<u>Option b:</u> 50.0 g water, $C_{water}=4.18J/g^oC$

We are given:

$m=50.0g\\C_{water}=4.18J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 4.18J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 4.18}=0.96^oC$

Change in temperature = 0.96°C

<u>Option b:</u> 25.0 g Pb, $C_{Pb}=0.128J/g^oC$

We are given:

$m=50.0g\\C_{Pb}=0.128J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC$

Change in temperature = 62.5°C

<u>Option d:</u> 25.0 g Ag, $C_{Ag}=0.235J/g^oC$

We are given:

$m=25.0g\\C_{Ag}=0.235J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.235J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.235}=34.04^oC$

Change in temperature = 34.04°C

<u>Option e:</u> 25.0 g granite, $C_{granite}=0.79J/g^oC$

We are given:

$m=25.0g\\C_{Fe}=0.79J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC$

Change in temperature = 10.13°C

Hence, the smallest temperature change is shown by water.

5 0

3 years ago

A piece of mental with a mass of 106 g is placed in a 50 mL graduated cylinder.The volume rises from 20 mL to 31 mL. What is the

garik1379 [7]

Answer:

9.64g/mL

Explanation:

Given parameters:

Mass of the metal = 106g

Volume of cylinder = 50mL

Volume difference = 31mL - 20mL = 11mL

Unknown:

Density of the metal = ?

Solution:

To find the density of the metal, we use;

Density = $\frac{mass}{volume}$

Density = $\frac{106}{11}$ = 9.64g/mL

8 0

2 years ago