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3 years ago

What are the 3 main types of clouds?

Chemistry

1 answer:

Vesna [10]3 years ago

4 0

Answer:

Cumulus, Cirrus, and Stratus

Explanation:

So Cumulus Clouds are those puffy-shaped clouds, the ones that look the most solid like you could just walk on them. Cirrus are those wispy clouds that are often very high up. And Stratus Clouds are the low clouds that often cover the entire sky.

hope this helps:)

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A chemist decomposes several samples of water into hydrogen and oxygen and weighs or more correctly measures the mass of the hyd

MariettaO [177]

Answer:

A. Hydrogen and oxygen combines in a constant mole ratio in all the three water samples

B. Carbon and oxygen are combined in a constant mole ratio in all the three samples of carbon dioxide

C. All pure samples of a compound contain the same elements combined in the same proportion by mass

D. Since the same elements are always combining to form a certain compound, and the atoms of each element has its own mass, the atoms of each element combining to form the compound do so in a fixed proportion by mass.

Explanation:

A. molar mass of hydrogen = 1.0 g/mol; molar mass of oxygen = 16 g/mol

The molar ratio of elements in a compound gives the proportion each element is combined with the other by mass.

molar ratio of hydrogen to oxygen in the samples:

Sample 1: Hydrogen; 1.5/1 = 1.5: Oxygen; 12/16 = 0.75

molar ratio = 1.5/0.75 = 2 : 0.75./0.75 = 1

molar ratio = 2:1

Sample 2: Hydrogen; 2/1 = 2: Oxygen; 16/16 = 1

molar ratio = 2/1 = 2 : 1/1 = 1

molar ratio = 2:1

Sample 3: Hydrogen; 2.5/1 = 2.5: Oxygen; 20/16 = 1.25

molar ratio = 2.5/1.25 = 2 : 1.25/1.25 = 1

molar ratio = 2:1

Hydrogen and oxygen combines in a constant mole ratio in all the three water samples

B. molar mass of carbon = 12 g/mol; molar mass of oxygen = 16 g/mol

molar ratio of carbon to oxygen in the samples:

Sample 1: Carbon; 0.5/12 = 0.04 : Oxygen; 1.3/16 = 0.08

molar ratio = 0.04/0.04 = 1 : 0.08/0.04 = 2

molar ratio = 1:2

Sample 2: Carbon; 1.0/12 = 0.083 : Oxygen; 2.7/16 = 0.168

molar ratio = 0.083/0.083 = 1 : 0.168/0.083 = 2

molar ratio = 1:2

Sample 3: Carbon; 1.5/12 = 0.125 : Oxygen; 4.0/16 = 0.250

molar ratio = 0.125/0.125 = 1: 0.250/0.125 = 2

molar ratio = 1:2

Carbon and oxygen are combined in a constant mole ratio in all the three samples of carbon dioxide

C. All pure samples of a compound contain the same elements combined in the same proportion by mass

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3 years ago

12.2 g of N₂ gas at 1132 torr and 91°C has a volume of

Bingel [31]

Answer:

8.73 L

Explanation:

First, you need to convert grams to moles using the molar mass.

Molar Mass (N₂): 2(14.009 g/mol)

Molar Mass (N₂): 28.018 g/mol

12.2 grams N₂ 1 mole
---------------------- x ------------------------ = 0.435 moles N₂
28.018 grams

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (torr)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 torr*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.

P = 1132 torr R = 62.36 torr*L/mol*K

V = ? L T = 91 °C + 273.15 = 364.15 K

n = 0.435 moles

PV = nRT

(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)

(1132 torr)V = 9888.015

V = 8.73 L

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