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Marat540 [252]
3 years ago
5

A swimming-pool worker wants the pool's pH to be 7.2. She comes by to test the water and finds that the pH is 9.2. What should s

he do to correct this situation?
A. Add water.

B. Add base.

C. Add acid.

D. Do nothing.
Chemistry
2 answers:
aksik [14]3 years ago
8 0

Answer : The correct option is, (C) Add acid.

Explanation :

As we know that, the pH measures the acidity and basicity of a substance.

The pH range for acidic solution is, 0.1 to 6.9

The pH range for basic solution is, 7.1 to 14

For neutral solution the pH is, 7

As per question, the worker wants the pH of the swimming pool is, 7.2 that means slightly basic. But by testing the water, she found that the pH is, 9.2 that means highly basic. So, to correct the pH of swimming pool that is 7.2 she should add an acid into the water to overcome the basicity of the water.

Hence, the correct option is, (C) Add acid.

cestrela7 [59]3 years ago
7 0

Answer:

The correct answer is option C.

Explanation:

The pH of the solution is negative logarithm of hydrogen ion concentration in the aqueous solution.

pH=-\log[H^+]

  • Higher the hydrogen ion concentration lower will be the pH.Hence, acidic
  • Lower the hydrogen ion concentration higher will be the pH.Hence, alkaline.

The pH of the pool = 9.2

9.2=-\log[H^+]

[H^+]=6.3096\times 10^{-10} M

The pH of the pool desired by worker = 7.2

7.2=-\log[H^+]'

[H^+]'=6.3096\times 10^{-8} M

Hydrogen ion needed tom vahnge pH of the pool from 9.2 to 7.2 is

:[H^+]'-[H^+]=6.3096\times 10^{-8} M-6.3096\times 10^{-10} M

=6.2465\times 10^{-8} M

For hydrogen ions worker has to add acid which will give hydrogen ion in its aqueous from. Hence, correct answer is option C.

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Amanda [17]
<span>you have to find the differences of electronegativity for the atoms joined by the bond. if their diff is <0.4,
then it's non-polar if it's between 0.4 to 1.7
then it's polar 1.7 and up it's ionic Electronegativity values can be found on most periodic tables.</span>
5 0
2 years ago
When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo
Marta_Voda [28]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

b)

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

7 0
2 years ago
Which statement best describes the organelles in a cell
Bas_tet [7]

Answer:

(2) Organelles must work together and their

activities must be coordinated

Explanation:

Organelles are usually located in cells. They are saddled with the role of performing specific functions in the cells for the overall functioning of life. In eukaryotic cells, the organelles are membrane bounded but in prokaryotic or primitive cells such is not the case.

Examples of cell organelles are ribosome, food vacuole, nucleus e.t.c. Just like organs in the body, organelles must work together in order to enhance life.

5 0
2 years ago
Calculate the standard heat of reaction for the following methane-generating reaction of methanogenic bacteria: 4CH3NH2(g) + 2H2
PIT_PIT [208]

<u>Answer:</u> The standard heat for the given reaction is -138.82 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4CH_3NH_2(g)+2H_2O(l)\rightarrow 3CH_4(g)+CO_2(g)+4NH_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]

We are given:

\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-46.1kJ/mol\\\Delta H_f_{(CH_4(g))}=-74.8kJ/mol\\\Delta H_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H_f_{(CH_3NH_2(g))}=-22.97kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(3\times (-74.8))+(1\times (-393.5))+(4\times (-46.1))]-[(4\times (-22.97))+(2\times (-285.8))]\\\\\Delta H_{rxn}=-138.82kJ

Hence, the standard heat for the given reaction is -138.82 kJ

3 0
3 years ago
How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?
Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

=  heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0
3 years ago
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