If the 50th and 51st terms of an arithmetic sequence are 140 and 142, find the 1st term

Mathematics

1 answer:

morpeh [17]3 years ago

4 0

Answer:

The first term is 42.

Step-by-step explanation:

The common difference is 142 - 140 = 2 so we have

50th term = a1 + 2(50 -1) = 140 where a1 is the first term

a1 + 98 = 140

a1 = 140 - 98 = 42.

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