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Rufina [12.5K]
3 years ago
9

W(−4+z)=mz+17 solve for z

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0
Z =(17 + 4w)/(w - m) I believe
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Please solve this please​
ale4655 [162]

Answer:

C) \frac{2z+15}{6x-12y}

E) \frac{7d+5}{15d^2+14d+3}

F) \frac{-7a-b}{6b-4a}

Step-by-step explanation:

C)

One is given the following equation

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is (6x-12y). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

Simplify,

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}

\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}

\frac{6z+6-6z+9+2z}{6x-12y}

\frac{2z+15}{6x-12y}

E)

In this case, one is given the problem that is as follows:

\frac{2}{3d+1}-\frac{1}{5d+3}

Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ((3d+1)(5d+3))

\frac{2}{3d+1}-\frac{1}{5d+3}

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

Simplify,

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}

\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}

\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}

\frac{10d+6-3d-1}{(3d+1)(5d+3)}

\frac{7d+5}{(3d+1)(5d+3)}

\frac{7d+5}{15d^2+14d+3}

F)

The final problem one is given is the following:

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is (6b-4a). Multiply the first fraction by a certain value to attain this denomaintor,

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

Simplify,

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

\frac{-6a}{6b-4a}-\frac{a+b}{6b-4a}

\frac{(-6a)-(a+b)}{6b-4a}

\frac{-6a-a-b}{6b-4a}

\frac{-7a-b}{6b-4a}

4 0
3 years ago
I’ll mark as BRANLIEST!!
Nikitich [7]

Answer:

1. 2x-20

2. 4(x+3)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
All of them!!!! Thanks for the help!!!!
podryga [215]
Okay so the formula is y2-y1/ x2-x1

(X,Y) for example (2,7). That means 2=X and 7=Y. So I’ll do your first problem and you do the rest. (0,0) (3,3) remember y2-y1 over x2-x1. So 3-0=3 and 3-0 =3 so slope is 3/3. Simplified 1
6 0
3 years ago
Plz plz plz help me I need it now!! I not gonna bribe you tho
NeX [460]

Answer:

thanks I guess interesting tho

5 0
4 years ago
Read 2 more answers
Rhombus STAR has vertices S(-1,2), T(2,3), A(3,0), and R(0,-1).What is the perimeter of rhombus STAR?ABCD√344√34√104√10
slamgirl [31]

INFORMATION:

We know that:

- Rhombus STAR has vertices S(-1,2), T(2,3), A(3,0), and R(0,-1)

And we must calculate the perimeter of the rhombus

STEP BY STEP EXPLANATION:

To calculate it, we must find first the measure of one of the sides.

We can find one of the sides calculating the distance between two consecutive vertices.

So, calculating the distance between vertices S and T

\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(2-(-1))^2+(3-2)^2} \\ d=\sqrt{3^2+1^2} \\ d=\sqrt{10} \end{gathered}

Finally, to find the perimeter, we need to use that the rhombus has 4 equal sides. So, we the perimeter would be

\begin{gathered} perimeter=4\times\sqrt{10} \\ perimeter=4\sqrt{10} \end{gathered}

ANSWER:

D. 4√10

5 0
1 year ago
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