Answer:
Answer B is the correct answer: "<em>Motion of one projectile as seen from the other is a straight line.</em>"
Explanation:
Let's write the equations of motion for each projectile, using that projectile 
is launched with velocity which has components associated with the angle of launching, given in x and y coordinates as: 
.
Similarly, assume that projectile b is launched with velocity 
with components due to the launching angle = 
then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:
therefore, from the frame of reference of projectile "b", the x and y position of projectile "" would be:
which is linear in "t"
![y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t](https://tex.z-dn.net/?f=y_%7Ba%5C%2C%5C%2Cb%7D%3Dy_a-y_b%3D%20a_y%5C%2Ct-%5Cfrac%7B1%7D%7B2%7D%20g%5C%2Ct%5E2-%5Cleft%5B%20b_y%5C%2Ct-%5Cfrac%7B1%7D%7B2%7D%20g%5C%2Ct%5E2%5Cright%5D%3D%28a_y-b_y%29%5C%2Ct)
which is also linear in t.
Therefore the motion of one projectile with reference to the other is a straight line (answer B)
Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.
<span>Δ PE = m g ( h1 - h2 ) = 0.25 * 9.8 ( 0.541 - 0.127 ) = 2.45 * 0.414 = 1.0143 J
Δ PE = KE = 1 / 2 m V^2
1 / 2 m V^2 = 1.0143--- v^2 = 1.0143 * 2 / 0.25 = 8.1144 --- v= 2.8486 m/s</span>
Answer:
0.45 seconds
Explanation:
Letting the value of g = 10 m/s/s
final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)
initial velocity(u) = 4.5 m/s
acceleration = -10 m/s/s (since the gravity is acting against the egg)
time = t seconds
From the first equation of motion:
<em>v = u + at</em>
<em>0 = 4.5 + (-10)t</em>
<em>t = -4.5 / -10</em>
t = 0.45 seconds
Answer:
,Assume that the average volume of an adult human body is one-tenth
cubic meter (0.10 m) and that there are two billion (2.0 x 109)
adults in the world.
a. What would be the total volume of all the adults in the world?
b. Compute the length of one edge of a cubic container that has a
volume equal to the volume of all the adults in the world.
