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xxMikexx [17]
3 years ago
15

A 7.1 resistor and a 4.8 resistor are connected in series with a battery. the potential difference across the 4.8 resistor is me

asured as 12 v. find the potential difference across the battery. v
Physics
1 answer:
Taya2010 [7]3 years ago
4 0
For resistors in series in a DC circuit, the potential difference is proportional to the resistance.

The voltage V across the 7.1 ohm resistor can be found from the proportion
   V/7.1 = 12/4.8
   V = 7.1*12/4.8 = 17.75

The potential difference at the battery terminals is the sum of the potential differences across the two series resistors.
   Vbatt = 17.75 V + 12 V
   Vbatt = 29.75 V
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This phenomenon is as a result of static friction created by the tumbling clothes. Static friction results from the rubbing together of two or mores objects or body and electrons are stripped from one surface of the clothes more than the other. This creates an electrostatic force of attractions between the positive charges on one cloth and the negative charges on the other cloth.(unlike charges attract).
5 0
2 years ago
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An FM radio station broadcasts electromagnetic radiation at a frequency of 93.5 MHz. The wavelength of this radiation is _______
Alborosie

Answer:

3.21

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength


c is the speed of light having value 3\times 10^8\ m/s

Given, Frequency = 93.5 MHz = 93.5\times 10^{6}\ Hz

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

Wavelength=\frac{3\times 10^8}{93.5\times 10^{6}}\ m

Wavelength=3.21 \ m

<u>Answer - A.</u>

7 0
3 years ago
What is the frequency of a wave if the speed is 24 m/s and the wave is 2 meters
vekshin1
Velocity=frequency(wavelength)
24m/s=f(2m)
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4 0
3 years ago
Some expressways are curved, banked and designed to maximize ___________ at higher speeds.
Liono4ka [1.6K]

Answer:

Safety

Explanation:

Expressways are banked to resist centifugal action

6 0
2 years ago
Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid
Korolek [52]

Answer:

a

    z= 2.5 \ m

b

   z =  (1 \ m ,  4 \ m )

Explanation:

From the question we are told that

     Their distance apart is  d =  5.00 \ m

      The  wavelength of each source wave \lambda =  6.0 \ m

Let the distance from source A  where the construct interference occurred be z

Generally the path difference for constructive interference is

              z - (d-z) =  m \lambda

Now given that we are considering just the straight line (i.e  points along the line connecting the two sources ) then the order of the maxima m =  0

  so

        z - (5-z) =  0

=>     2 z - 5 =  0

=>     z= 2.5 \ m

Generally the path difference for destructive  interference is

           |z-(d-z)| = (2m + 1)\frac{\lambda}{2}

=>         |2z - d |= (0 + 1)\frac{\lambda}{2}

=>        |2z - d| =\frac{\lambda}{2}

substituting values

          |2z - 5| =\frac{6}{2}

=>      z  =  \frac{5 \pm 3}{2}

So  

      z =  \frac{5 + 3}{2}

      z =  4\ m

and

      z =  \frac{ 5 -3 }{2}

=>   z =  1 \ m

=>    z =  (1 \ m ,  4 \ m )

7 0
3 years ago
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