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xxMikexx [17]
3 years ago
15

A 7.1 resistor and a 4.8 resistor are connected in series with a battery. the potential difference across the 4.8 resistor is me

asured as 12 v. find the potential difference across the battery. v
Physics
1 answer:
Taya2010 [7]3 years ago
4 0
For resistors in series in a DC circuit, the potential difference is proportional to the resistance.

The voltage V across the 7.1 ohm resistor can be found from the proportion
   V/7.1 = 12/4.8
   V = 7.1*12/4.8 = 17.75

The potential difference at the battery terminals is the sum of the potential differences across the two series resistors.
   Vbatt = 17.75 V + 12 V
   Vbatt = 29.75 V
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A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate
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The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

<h3>What is impedance Z of the circuit?</h3>

The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.

Z=\dfrac{V}{I}

Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.

The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,

316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A

The impedance Z of the circuit is,

Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm

Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

Learn more about the impedance Z of the circuit here:

brainly.com/question/24225360

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