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Dimas [21]
4 years ago
11

Perform the indicated operations and write the result in the form of a + bi (3 - 2i)(4 + 3i)

Mathematics
1 answer:
Akimi4 [234]4 years ago
3 0
Remember:
i=√-1
i²=(√-1)(√-1)=-1


(3-2i)(4+3i)=
=(3*4)+(3*3i)+(-2i*4)+(-2i*3i)
=12+9i-8i-6i²
=12+(9i-8i)-(6*-1)
=12+i+6
=18+i

Answer: (3-2i)(4+.3i)=(18+i)


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