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lozanna [386]
3 years ago
9

A stadium has 47,000 seats. Seats sell for ​$28 in Section​ A, ​$24 in Section​ B, and ​$20 in Section C. The number of seats in

Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,187,600 from each​ sold-out event. How many seats does each section​ hold?
Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
A:23,500 seats
B and C: both have 11,750 seats
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Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke
FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

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3 years ago
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2 years ago
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Flauer [41]

Answer:

\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}

or

\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots

or

Multiply the numerator and the denominator by the same number:

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Subtract 3 from each side to isolate the x and you get x=y-3
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d1i1m1o1n [39]

the area is 180 cm. to find the perimeter you would do 15+15+14+14 to get 54 cm. So for area you do (l×w) which is 15×14=180.

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2 years ago
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