Use the graphs of f and g to solve Exercises 87, 88, and 89.
1 answer:
Answers and explanations:
87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]
88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)
89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!
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Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
Answer:
Step-by-step explanation:
We are given the following in the question:
Let be the proportion of the internet sales and
be the proportion of the store sale.
Hypothesis:
We have to conduct a hypothesis to check that the Internet sales are more than 10 percent higher than store sales.
Thus, we can design the null and alternative hypothesis as:
Alternate Hypothesis:
The alternate hypothesis states that the proportion of the internet sales is greater than the proportion of store sales by 10 percent.