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solmaris [256]
3 years ago
12

Which statement correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodi

c table?
The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.
The alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion.
The alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal.
The alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.
Chemistry
2 answers:
Kitty [74]3 years ago
7 0
"The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion" is the one statement among the choices given in the question that <span>correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodic table. The correct option among all the options is first option.</span>
Black_prince [1.1K]3 years ago
5 0

Answer: The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.

Explanation: Group 1 elements are called as alkali metals and group 2 elements are called as alkaline earth metals.

For example, Li is an alkali metal and Be is an alkaline earth metal.

Lithium(Li) has an atomic number of 3 and the electronic configuration is:

Li: 1s^22s^1

Thus lithium has to lose 1 electron and acquire 1+ charge to attain nearest noble gas configuration.

Li^+:1s^2

Berrylium(Be) has an atomic number of 4 and the electronic configuration is:

Be: 1s^22s^2

Thus berrylium has to lose 2 electrons and acquire 2+ charge to attain nearest noble gas configuration.

Be^{2+}:1s^2


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Urgent!! A chemist measured 5.2 g copper(II) bromide tetrahydrate (CuBr2•4(H2O)). How many moles were measured out? Answer in un
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Composition of Dry AirGas Percent by Volume (%)Nitrogen (N2) 78Oxygen (O2) 21Argon (Ar) 0.9Carbon dioxide (CO2) 0.04 What volume
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Answer:

40.95 L

Explanation:

We'll begin by calculating the number of mole in 12.3 g of O₂. This can be obtained as follow:

Mass of O₂ = 12.3 g

Molar mass of O₂ = 16 × 2 = 32 g/mol

Mole of O₂ =?

Mole = mass / Molar mass

Mole of O₂ = 12.3 / 32

Mole of O₂ = 0.384 mole

Next, we shall determine the volume occupied by 0.384 mole of O₂. This can be obtained as follow:

Number of mole (n) of O₂ = 0.384 mole

Pressure (P) = 1 atm

Temperature (T) = 273 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of O₂ =?

PV = nRT

1 × V = 0.384 × 0.0821 × 273

V = 0.384 × 0.0821 × 273

V = 8.6 L

Thus, the volume of O₂ is 8.6 L

Finally, we shall determine the volume of air that contains 8.6 L of O₂. This can be obtained as follow:

Volume of O₂ = 8.6 L

Percentage of O₂ in air = 21%

Volume of air =?

Percentage of O₂ = Vol of O₂ / Vol of air × 100

21% = 8.6 / Vol of air

21 / 100 = 8.6 / Vol of air

Cross multiply

21 × Vol of air = 100 × 8.6

21 × Vol of air = 860

Divide both side by 21

Volume of air = 860 / 21

Volume of air = 40.95 L

Therefore, the volume of air is 40.95 L.

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3 years ago
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