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stiv31 [10]
3 years ago
14

Solve each using substitution Y=3x-5 2x+3y=29 3x+y=30 Y=5x+6

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0
Question 1: X=4
Question 2: X=4
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4. y=-3/4 +1 I could be wrong but I think this is right
5 0
3 years ago
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
I REALLY NEED THIS SOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOPER BADLY
VLD [36.1K]

Answer:

8.4 * 10^6

Step-by-step explanation:

8.4 * 10^6

1 million = 1 * 10^6

8 million 4 hundred thousand is 8.4 * 10^4 because this number is 8.4 times bigger than a million.

6 0
3 years ago
Write 0.51 as a fraction in simplest form please help!
KonstantinChe [14]
51/100

Explain: you start with 51/100 and that can’t be simplified any further :) hope this helped
4 0
4 years ago
1,275/5 find the unit rate​
Pachacha [2.7K]

Answer:

255

Step-by-step explanation:

1,275/5 = 255

3 0
3 years ago
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