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andre [41]
3 years ago
11

Please help me idk this

Mathematics
1 answer:
masha68 [24]3 years ago
7 0

Answer:

26 would be you answer. Hope this helps!

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What’s 5e+|-12+f|+g e=-3 f=4 g=-1
AleksAgata [21]

Answer:

-8

Step-by-step explanation:

5 times -3 is -15

absolute value of -12 plus 4 is 8

-15 plus 8 plus -1 is -8

8 0
3 years ago
Please help<br><br> Right triangles and trigonometry quiz two on Khan Academy
Sedbober [7]

Answer:

AC = 2.44

Step-by-step explanation:

Reference angle = 26°

Opposite side = AC = ?

Adjacent side = BC = 5

Applying TOA, we have:

Tan 26 = opp/adj

Tan 26 = AC/5

multiply both sides by 5

Tan 26 × 5 = AC

AC = 2.44 (nearest hundredth)

8 0
2 years ago
Complete the chart to find the mean,variance,and standard deviation. 45 340 400 825
hoa [83]

Answer:

<u>A. Mean =  402.5</u>

<u>B. Variance = 77,556.25</u>

<u>C. Standard Deviation =  278.49</u>

Step-by-step explanation:

Let's calculate the mean, variance and standard deviation of the set of numbers given:

A. Mean = (45 + 340 + 400 + 825)/4 = 1,610/4 =<u> 402.5</u>

B. Variance [(45 - 402.5)² + (340 - 402.5)² + (400 - 402.5)² + (825 - 402.5)²]/4 =  [(127,806.25 + 3,906.25 +6.25 + 178,506.25/4 =<u> </u><u>77,556.25</u>

C. Standard Deviation = √Variance = √77,556.25 =<u> 278.49</u>

7 0
3 years ago
Manny bought a brand new car for $29,750. The car depreciates in value by 12% each year. Find the value of the car after 6 years
Arte-miy333 [17]

Answer: $13,846.02

Step-by-step explanation:

The car cost $29,750 when it was first bought.

It will then depreciate at a rate of 12% per year. This means that the value of the car reduces by 12% per year.

To find the value of the car in the 6th year, you can use the compound interest formula:

= Value of car * ( 1 - rate) ^ no. of years

= 29,750 * ( 1 - 12%)⁶

= ‭13,816.021581824‬

= $13,846.02

6 0
2 years ago
At the beginning of the bake sale merry set aside two pies for herself Kate bought half of the remaining pies for a birthday par
nirvana33 [79]
So.. .at the beginning of the sale, there was a total of "x" pies

now, let's see what happened to those pies
\bf \begin{array}{lrlll}&#10;&pies\\\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\\&#10;&#10;Mary&x-2\\\\&#10;Kate&\cfrac{x-2}{2}\\\\&#10;\textit{pies sold}&10\\\\&#10;\textit{pies leftover}&14&#10;\end{array}

so, we had "x"
then Mary took 2, she left x - 2
Kate took half of that (x-2)/2
then 10 were sold, and 14 leftover

if we subtract all those figures, and solve for "x",
we should get what "x" was, so \bf (x-2)-\left( \cfrac{x-2}{2} \right)-10-14=0

notice, if we subtract what Mary took, and Kate, and the sold and leftover, from the original "x", we would end up with no pies :)

so.. just solve for "x"
6 0
3 years ago
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