Given:
perimeter of a sector of a circle = 7cm
area of a sector of a circle = 3 cm²
Perimeter of a sector = 2r + l = 2r + rΘ
2r + 2Θ = 7
area of a sector = (Θ/2π) πr² = (Θ/2)r²
<span>(Θ/2)r² = 3 </span>⇒ Θ = 6/r²
2r + rΘ = 7
2r + r(6/r²) = 7
2r + 6/r = 7
r(2r + 6/r) = r*7
2r² + 6 = 7r
2r² - 7r + 6 = 0
2r² - 4r - 3r + 6 = 0
2r(r - 2) - 3(r - 2) = 0
(2r - 3) (r - 2) = 0
2r - 3 = 0
2r = 3
r = 3/2 or 1 1/2
r - 2 = 0
r = 2
Possible radii are 2 cm and 1 1/2 cm.
Answer: D. She can check to see if the rate of change between the first two ordered pairs is the same as the rate of change between the first and last ordered pairs.
Step-by-step explanation:
Answer:
"A half of a class and a half of a student got A on a test" this confuse me for a bit.... but i hope i got the right answer
Step-by-step explanation:
call number of students in the class is a
A half of a class and a half of a student got A on a test ->1/2 a +0.5 ?
1/2 a + 0.5 + 1 = 2/3 a
-> 1/2 a +1.5 = 2/3 a
-> 1.5 = 1/6a
-> a = 9
Answer:
The total for the meal would be $17.19 as the 15% tip is $2.24
Step-by-step explanation:
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
<h3>What is a quadratic equation?</h3>
It's a polynomial with a worth of nothing.
There exist polynomials of variable power 2, 1, and 0 terms.
A quadratic condition is a condition with one explanation where the degree of the equation is 2.
Domain and range of linear and quadratic functions
Let the linear equation be y = mx + c.
Then the domain and the range of the linear function are always real.
Let the quadratic equation will be in vertex form.
y = a(x - h)² + k
Then the domain of the quadratic function will be real.
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
More about the quadratic equation link is given below.
brainly.com/question/2263981
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