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algol13
3 years ago
7

Solve the systems of equations 6x+3y=9 2x+3y=1

Mathematics
1 answer:
patriot [66]3 years ago
7 0
Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.

Do this by changing the equations so that the coefficients of either x or y add up to 0.

Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0

Multiply 2nd equation by -1.

6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8

Solve for x
4x = 8
x = 8/4 = 2

Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1

Therefore solution is (2,-1)
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Can someone plz help me with this one problem plzzzzz I’m marking brainliest!!!
Andre45 [30]
2=6
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8 0
2 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
Given f(x)=1/x+5 and g(x)=x-2
vladimir1956 [14]

For this case we have the following functions:

f (x) = \frac {1} {x + 5}\\g (x) = x-2

We must find f (g (x)). So:

f (g (x)) = \frac {1} {(x-2) +5} = \frac {1} {x-2 + 5} = \frac {1} {x + 3}

Finally we have to:

f (g (x)) = \frac {1} {x + 3}

For the function to be defined the denominator must be different from 0. That is x different from -3.

Answer:

Option B

3 0
3 years ago
What shape do degree 3 functions have?
weqwewe [10]

Answer: Third degree polynomials are also known as cubic polynomials. Cubics have these characteristics: One to three roots. Two or zero extrema.

HOPE THIS HELPS

Please brainliest

5 0
3 years ago
Read 2 more answers
Please Help Me!
luda_lava [24]

Answer:

A. they both have 4 right angles

B. a sqaure has 4 even sides, a rectangle doesnt

c. they both have 4 even sides

d. rhombi has 2 acute and 2 obtuse angles

e. Parallelograms are a quadrilateral where diagonals bisect each other, opposite sides are parallel by definition, opposite sides are congruent and consecutive angles are supplementary.

6 0
2 years ago
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