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2 years ago

Solve the systems of equations 6x+3y=9 2x+3y=1

1 answer:

7 0

Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.

Do this by changing the equations so that the coefficients of either x or y add up to 0.

Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0

Multiply 2nd equation by -1.

6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8

Solve for x
4x = 8
x = 8/4 = 2

Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1

Therefore solution is (2,-1)

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Find mZXZx(5t - 13°Y(3t+ 3)

trapecia [35]

The diagram provided is an isosceles triangle. An isosceles triangle has two sides having equal measure and two base angles also having equal measure.

From the marks on the triangle given, line ZX and line ZY are equal in length. This also means angle X and angle Y are equal in measure.

Therefore, we would have;

$\begin{gathered} 5t-13=3t+3 \\ \text{Collect all like terms and you'll have,} \\ 5t-3t=3+13 \\ 2t=16 \\ \text{Divide both sides by 2} \\ \frac{2t}{2}=\frac{16}{2} \\ t=8 \\ \text{If t=8, then} \\ 5t-13=5(8)-13 \\ 5t-13=40-13 \\ 5t-13=27 \end{gathered}$

This means angle X and angle Y both equal 27 degrees each.

Note that the sum of angles in a triangle is 180. Therefore, in triangle ZXY,

$undefined$

7 0

7 months ago

An above swimming pool is leaking after 1/2 hour the pool has leaked 7/8 of a gallon of water

Luden [163]

The answer to your question are <span>1.75</span>

8 0

3 years ago

You need to earn at least $100. You earn $8.00 per hour mowing lawns. Write and solve an inequality that represents the number o

leonid [27]

Answer:

subject?

Step-by-step explanation:

7 0

3 years ago

Solve for x 11x+4<15 OR 12x−7>−25

never [62]

Isolate the x in both cases. What you do to one side, you do to the other.

11x + 4 < 15

Subtract 4 from both sides

11x + 4 (-4) < 15 (-4)

11x < 11

isolate the x, divide 11 from both sides

11x/11 < 11/11

x< 1

x < 1 is your answer for the first one

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Again, isolate the x.

12x - 7 > -25

Add 7 to both sides

12x - 7 (+7) > -25 (+7)

12x > -18

Isolate the x, divide 12 from both sides

12x/12 > -18/12

x > -1.5 is your answer for the second one.

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hope this helps

3 0

3 years ago

Read 2 more answers

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

3 years ago