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Alexeev081 [22]
4 years ago
11

Which lunar phrase follows a waning crescent phase?

Chemistry
1 answer:
irakobra [83]4 years ago
3 0
A third quarter follows a waning crescent.<span />
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Write a balanced equation for the combustion of hexane, C6H14 (l)
stich3 [128]
The combustion of hexane (C6H14), a component of gasoline, is represented by the balanced chemical equation: 2 C6H14(l) + 19 O2(g) " 12 CO2(g) + 14 H2O(g). If 1.0 mole of hexane undergoescombustion, moles of O2 are required.
8 0
4 years ago
A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
nikitadnepr [17]

The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Given data:

M= 0.420M

mass = 64.0 grams

Molar Mass= 74g/mol

To find:

The volume of solution=?

The calculation for a number of moles:

n= \frac{m}{M}

n= \frac{64}{70}

n= 0.91 moles

Molarity=  \frac{n}{V}

V= \frac{0.91}{0.420}

V= 2.1768 litres

Thus, the volume of the solution is 2.18 litres.

Find more information about Molarity here:

brainly.com/question/26873446

#SPJ1

6 0
2 years ago
Given the following reaction: 2N2O5=2N2O4+O2, if the rate of oxygen production is 0.15M/min, determine:
astraxan [27]

Answer:

a. r_{N_2O_5}=-0.075M/min

b. r_{N_2O_4}=0.075M/min

Explanation:

Hello.

In this case, according to the balanced chemical reaction, we can write the law of rate proportions:

\frac{r_{N_2O_5}}{-2} =\frac{r_{N_2O_4}}{2} =\frac{r_{O_2}}{1}

Thus, we proceed as follows:

a. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_5}}{-2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_5}=\frac{r_{O_2}}{-2}  =\frac{0.15M/min}{-2}\\\\ r_{N_2O_5}=-0.075M/min

b. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_4}}{2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_4}=\frac{r_{O_2}}{2}  =\frac{0.15M/min}{2}\\\\ r_{N_2O_4}=0.075M/min

Best regards!

8 0
3 years ago
Name the ions in water acidified with dilute sulphuric acid
Vladimir [108]

Answer:

H + ions are attracted to the cathode , gain electrons and form hydrogen gas. OH - ions are attracted to the anode , lose electrons and form oxygen gas.

6 0
4 years ago
Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?
timurjin [86]
It should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)
8 0
3 years ago
Read 2 more answers
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