The combustion of hexane (C6H14), a component of gasoline, is represented by the balanced chemical equation: 2 C6H14(l) + 19 O2(g) " 12 CO2(g) + 14 H2O(g). If 1.0 mole of hexane undergoescombustion, moles of O2 are required.
The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.
<h3>Define the molarity of a solution.</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:
M= 0.420M
mass = 64.0 grams
Molar Mass= 74g/mol
To find:
The volume of solution=?
The calculation for a number of moles:
n= 
n= 
n= 0.91 moles
Molarity= 
V= 
V= 2.1768 litres
Thus, the volume of the solution is 2.18 litres.
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Answer:
a. 
b. 
Explanation:
Hello.
In this case, according to the balanced chemical reaction, we can write the law of rate proportions:

Thus, we proceed as follows:
a. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

b. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

Best regards!
Answer:
H + ions are attracted to the cathode , gain electrons and form hydrogen gas. OH - ions are attracted to the anode , lose electrons and form oxygen gas.
It should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)