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mina [271]
3 years ago
15

What mass of aluminum will be deposited on the cathode if an electric current of 0.15 a is run for 4 5s when a solution of al(no

3 )3 is subjected to electrolysis?
Chemistry
1 answer:
marishachu [46]3 years ago
3 0

Mass of Al, m= ?

Molar mass of copper Al, M = 27.0 g/mol

time, t = 45 s

current , c = 0.15 A

valency of Al in Al(NO₃)₃ , z = +3

From Faraday's 1st law,

m = Mct/zF

where F = Faraday constant = 96500 C/mol

Substitute all the values,

m = [(27.0 g/mol) (0.15 A) (45 s)]/ [3] [96500 C/mol]

= 6.3 x 10⁻⁴ g

Mass of aluminium = 6.3 x 10⁻⁴ g

Therefore, mass of aluminium plated on electrode =  6.3 x 10⁻⁴ g

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The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p
Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

    Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g  

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}

(ii) Solve the relationship

 Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

    56x + 18(7.5 - x) = 267.3

      56x + 135 - 18x = 267.3

                        38x = 132.3

                            x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0
3 years ago
Given a fixed amount of gas help at a constant pressure, calculate the temperature to which the gas would have to be changed if
PIT_PIT [208]

Answer:

592 K or 319° C

Explanation:

From the statement of Charles law we know that the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure. Thus;

V1/T1= V2/T2

Initial volume V1 = 1.75 L

Initial temperature T1= 23.0 +273 = 296 K

Final volume V2= 3.50 L

Final temperature T2 = the unknown

T2= V2T1/V1= 3.50 × 296 / 1.75

T2 = 592 K or 319° C

4 0
2 years ago
An electron is a particle with a _____.
astra-53 [7]
The Answer is B.

*NEGATIVE CHARGE, FOUND OUTSIDE THE NUCLEUS*
5 0
2 years ago
Read 2 more answers
Upon heating a copper sample will expand, leading to a lower density? <br><br>A) True<br>B) False
Leona [35]

Answer;

The above statement is true

upon heating a copper sample will expand, leading to a lower density

Explanation;

-The density of solids decreased with increase in temperature and vice versa. The increase in temperature causes the volume of the solid to increase which as a result decreases the density as Density=Mass/Volume. The temperature of a body is the average kinetic energy of the molecules present in it.

In other words; The temperature of a body is the average kinetic energy of the molecules present in it. Therefore; when heat is supplied ( or temperature is increased) the average kinetic energy increases which increases the volume and thus density decreases.

8 0
3 years ago
What is the molarity of a solution containing 12.0 g of NaOH in 250.0 mL of solution?
riadik2000 [5.3K]

Answer:

1.196 M NaOH

Explanation:

Molarity = moles/Volume (L)

moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH

Volume solution = 250 mL = 0.250L

M = 0.299/0.250=1.196 M NaOH

3 0
2 years ago
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