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mina [271]
3 years ago
15

What mass of aluminum will be deposited on the cathode if an electric current of 0.15 a is run for 4 5s when a solution of al(no

3 )3 is subjected to electrolysis?
Chemistry
1 answer:
marishachu [46]3 years ago
3 0

Mass of Al, m= ?

Molar mass of copper Al, M = 27.0 g/mol

time, t = 45 s

current , c = 0.15 A

valency of Al in Al(NO₃)₃ , z = +3

From Faraday's 1st law,

m = Mct/zF

where F = Faraday constant = 96500 C/mol

Substitute all the values,

m = [(27.0 g/mol) (0.15 A) (45 s)]/ [3] [96500 C/mol]

= 6.3 x 10⁻⁴ g

Mass of aluminium = 6.3 x 10⁻⁴ g

Therefore, mass of aluminium plated on electrode =  6.3 x 10⁻⁴ g

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How many PO43? ions are in a mole of K3PO4?
adoni [48]

K₃PO₄ → 3K⁺ (aq) + PO₄³⁻(aq)

One mole of PO₄³⁻ ion gets dissociated from one mole of K₃PO₄

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ ions

One mole of PO₄³⁻ ions x  (6.022 x 10²³ ions/ 1 mole of PO₄³⁻ ions )

= 6.022 x 10²³ ions

Therefore , there are 6.022 x 10²³ PO₄³⁻ ions in a mole of K₃PO₄.

7 0
3 years ago
Please help!! 20 points!! Posted this previously and forgot to change it to 20 points but it is now
spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

Number of moles of NaHCO₃ = 0.571 mol

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

NaHCO₃ + C₃H₆O₃   →     CO₂  + C₃H₅NaO₃ + H₂O

Now we will compare the moles of CO₂ with NaHCO₃ from balance chemical equation.

                             NaHCO₃          :            CO₂

                                    1                :               1

                                 0.571            :            0.571

So number of moles of CO₂  produced are 0.571.

3 0
3 years ago
Read 2 more answers
Can you please help me (50 points)
Anna35 [415]

Answer:

P=15

N=59

Explanation:

Pic is blurry but I based my answer on bottom number being 74

4 0
2 years ago
515282 quarts into milliliters. I
Minchanka [31]

Answer:

487638640,7819

dndndnndndbxbdbdbdbdb

6 0
3 years ago
Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
madam [21]

actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

6 0
3 years ago
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