The bacteria in nasty environment undergoes multiple fission.
<h3><u>Explanation</u>:</h3>
The bacteria is a unicellular prokaryotic organisms that are found in each and every places of the world. They can survive in extremes of temperatures and pH. They can save themselves through special processes in the extreme climates.
The bacteria undergoes multiple fission in these climates. They cover themselves up with a strong and tough capsule inside which they undergo several Binary fissions. This leads to the formation of multiple cells enclosed with a capsule.
With the return of the favourable climate, the capsule rupture and these newly formed cells come out.
The number of neutrons is variable, resulting in isotopes, which are different forms of the same atom that vary only in the number of neutrons they possess. Together, the number of protons and the number of neutrons determine an element's mass number.
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Atomic number = 42
Name = Molybdenum
Atomic symbol = Mo
Group number = VI(B)6
Mo = Metal
How to find all valves of Z=42?
Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.
The atomic number of the element is 42
Therefore, the name of the element is Molybdenum
The atomic symbol of the element is Mo
The group number of is VI(B)6
Mo is a metal
Hence, the element is Molybdenum
Learn more about atomic symbol here :
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I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y,
for the following reason:
If you look at the combining masses of X and Y in
each of the two compounds,
The first compound contains 0.25g of X combined with
0.75g of Y
so the ratio (by mass) of X to Y = 1 : 3
The second compound contains 0.33 g of X combined with
0.67 g of Y
so the ratio (by mass) of X to Y = 1 : 2
Now, you suppose to prepare each of these two
compounds, starting with the same fixed mass of element Y ( I will choose 12g
of Y for an easy calculation!)
The first compound will then contain 4g of X and 12g
of Y
The second compound will then contain 6g of X and
12g of Y
<span>The ratio which combined
the masses of X and the fixed mass (12g) of Y
= 4 : 6
<span>or 2 : 3 </span>
So, the ratio of MOLES of X which combined with the
fixed amount of Y in the two compounds is also = 2 : 3 </span>
The two compounds given with the plausible formula must therefore contain
the same ratio.
