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PSYCHO15rus [73]
4 years ago
14

Answer this too, the BRAINIEST!

Mathematics
1 answer:
-Dominant- [34]4 years ago
8 0

Check out the attached image below for the steps on how to do this derivation.

------------

Some notes:

  • For line 2, I used the identity \sec^2\theta = \tan^2\theta+1
  • For line 7, I applied the reciprocal to both sides.
  • For line 8, I used the identity \cot\theta = \frac{1}{\tan\theta}
  • For line 9, I used the identty \cot^2\theta = \csc^2\theta - 1 which is a rearrangement of \cot^2\theta + 1 = \csc^2\theta
  • For lines 1 through 6, I'm isolating tan^2, so that I can later transform that into cot^2, which leads to csc^2. All of this is done through the identities mentioned above.

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