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makkiz [27]
2 years ago
8

Use the graph and the translation (x,y)

Mathematics
1 answer:
blsea [12.9K]2 years ago
3 0
There’s no picture..
You might be interested in
Please help, seriously confused
Rufina [12.5K]
Original height = original width = x mm

1. She made an enlarged copy...
height = 2x
width = 2x

2. She cut off a rectangle...
height = 2x
width = \frac{2}{3} *2x= \frac{4}{3}x

3.She doubled the width...
height = 2x
width = 2*\frac{4}{3}x = \frac{8}{3}x

height * width = area

2x * \frac{8}{3}x=139 \ 968  \\ \\ \frac{16}{3}x^2= 139 \ 968 \\\\ x^2=139 \ 968: \frac{16}{3}=139 \ 968 * \frac{3}{16}=  8 \ 748*3 = 26 \ 244 \\  \\ x= \sqrt{26 \ 244} = 162 \ mm

Original height was 162 mm 
6 0
3 years ago
Kevin and Randy Muise have a jar containing 36 ​coins, all of which are either quarters or nickels. The total value of the coins
borishaifa [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
6w + 2(4w - 7) simplified​
Gemiola [76]

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

8 0
3 years ago
Read 2 more answers
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
Hyxetdryufgukhchfxrdtygujhftyuhuhyguhjygyu
nikklg [1K]

Answer:

so the answer is: eijieljnqwsmiqwmx

did i answer it correctly let me know

Step-by-step explanation:

Destroy your keyboard by smashing each random word on the poor broken keyboard  

6 0
3 years ago
Read 2 more answers
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