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Ann [662]
3 years ago
6

Work out the volume of a cuboid 6cm by 4cm by 2.5cm

Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0
This should be a nice and simple answer to your question.

The formula for working out the volume of a cuboid is
Volume=Length×Width×Height

This can be shortened to
V=l×w×h
Or
V=lwh

So, now you know the formula, on to the question

Work out the volume of a cuboid 6cm by 4cm by 2.5cm

Find the relevant information

6cm 4cm and 2.5cm

Write out the formula

V=l×w×h

Substitute in the values

V=6×4×2.5

Solve the equation

V=60

Volume is always a cubed number so remember to add the cubed sign next to your answer (³)

So your final answer will be
Volume=60³

I hope that this has helped you.
Leokris [45]3 years ago
5 0
Do the LWH rule.
6 x 4 x 2.5=60cm cubed
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Step-by-step explanation:

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3 0
2 years ago
Help!! Which of the following best represents Z1 • Z2 select all that apply
AURORKA [14]

z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)

z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}

\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\

Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)

On simplifying, we get

Z_1* Z_2 =-3\sqrt{2}

<h2>Therefore, correct option is  1st option.</h2>
3 0
2 years ago
Which of the following is 10 times what the 5 represents in 8,145
Alexxx [7]

Answer:

A

Step-by-step explanation:

5 in 8145 is in the ones place. Hence 10 times of that

= 10 × 5

= 50

Hence answer is <u>A</u><u>.</u>

7 0
2 years ago
Read 2 more answers
Please Help! Easy!
irinina [24]

Answer:

The answer is B.

4 0
3 years ago
Read 2 more answers
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