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2 years ago

Solve the inequality for –5.3 ≥ 6.7 + 4.3 + q

Mathematics

2 answers:

Delicious77 [7]2 years ago

6 0

Answer:

q = -16.3

Step-by-step explanation:

–5.3 ≥ 6.7 + 4.3 + q

-5.3 ≥ 11 + q

-11 -11

-16.3 ≥ q

chubhunter [2.5K]2 years ago

3 0

I don’t know and don’t care so use a caucalator

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Help I will mark you brainly

Ludmilka [50]

Answer:

Hi there!!

The answer would be x=20 and y= 10 root 3 or on decimal it's 17.32.

explanation look in picture, alright. 

I hope it will help u....

5 0

2 years ago

Read 2 more answers

Which dimensions can create only one unique triangle?

s2008m [1.1K]

Answer:

<h2>The dimensions must all add up to 180°.</h2>

Step-by-step explanation:

For example;

Your triangles' angles are: 56, 77, and 47.

56 + 77 + 47 = 180

*You did not give me any values to solve for, but just since you didn't- I'v provided an example to assist you in doing it yourself. If you want me to solve your full equation please add the angles or 3 dimensions of the triangle.

<h3>I hope this helped!</h3>

3 0

2 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers

Ahhhh i need help like now !!!!!!!!!!!

ozzi

Answer:

x = 2

Step-by-step explanation:

Simplify both sides of the equation.

−20 = − 4x − 6x

−20 = −4x − 6x

−20 = (−4x − 6x)(Combine Like Terms)

−20 = −10x

Flip the equation.

−10x = −20

Divide both sides by -10.

-10x/-10 = -20/-10

x = 2

7 0

2 years ago

A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 15 minutes. Air traffic co

Sladkaya [172]

Answer:

y = (1/2)x + 15

Step-by-step explanation:

First, we need to identify the parts of the problem that we already know:

1) The pilot was originally scheduled to depart at 1600 (4:00 pm).

2) The pilot's departure was delayed by 15 minutes.

3) the traffic control approved a new flight plan that would allow the pilot to travel to her destination two times faster than her original flight plan.

For the problem's sake, let us pretend that the pilot's original flight plan was going to take two hours. Had he/she left at 4:00 pm, the pilot would have landed at 6:00 pm.

With a delay of 15 minutes, the duration of the flight would still remain constant, so the pilot would arrive at their destination two hours later, at 6:15 pm.

With the new flight plan, the pilot's travel time would be cut in half, so it would be 1/2 of x (time, in minutes, of original flight). Thus, her new flight time would only be one hour (60 minutes).

So, now we have to subtract 1/2 from the original flight time, as well as adding the 15 minute delay for departure. Now we can create a formula:

y = (1/2)x + 15

Y equals the total amount of time (in minutes) that it would take for the plane to leave. We divide x (total time of original flight) by 2, because her new flight plan will be twice as fast. Then we have to take into account the extra 15 minute delay!

8 0

3 years ago