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rodikova [14]
3 years ago
13

Please answer quickly I will give who ever answer this 50 POINTS AND MARKED AS BRAINIEST

Mathematics
2 answers:
professor190 [17]3 years ago
7 0
The answer would be D
mars1129 [50]3 years ago
3 0
The correct answer is D because it is the only true statement. All the other choices are not equivalent to each other. Hope I helped?
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Supply the missing reasons to complete the proof.
MAXImum [283]

Answer:

3. ASA

4. Corresponding sides of congruent triangles are congruent

Step-by-step explanation:

I marked this in the attached image. ∠B ≅∠E, ∠ACE ≅ ∠DCE, and the side between them BC ≅ EC, so the the triangles ΔACB and ΔDCE are congruent by ASA.

If the triangles are congruent, then all corresponding angles and sides are also congruent.

7 0
2 years ago
each wall requries 2 1\2 gallons of paint. ryan has 8 gallons of paint. find the number of walls ryan can paint.
adoni [48]
He can paint 3 walls completely

5 0
3 years ago
An article in a magazine discussed the length of time till failure of a particular product. At the end of theâ product's lifetim
diamong [38]

Answer:

Step-by-step explanation:

From the missing information;

Lets assume that;

\text{the exponential distribution mean = 500 thousand naira}

\text{Range 100 thousand} → \text{1 million naira}

∴

a)

X \sim exp (\dfrac{1}{500}) \\ \\  P( X \le x) = 1 - e^{\dfrac{-x}{500}} \\ \\ P(X < 700) = 1 - e^{\frac{-7}{5}} \\ \\  \mathbf{P(X< 700) = 0.75340}

b)

Y \sim \cup (100,1000) \implies P(Y \le y ) = \dfrac{y - 100}{1000-100} \\ \\ P(Y < 700) = \dfrac{600}{900} = 0.67

c)

P(X < 830)= 1 - e^{\frac{-830}{500}} \\ \\ P(X < 830)= 1 - 0.1901 \\ \\ P(X < 830)=0.8099 \\ \\  P(Y < 830) = \dfrac{730}{900} = 0.8111 \\ \\ Thus;\mathbf{ P(X < 0.8099) = P(Y< 0.8111)}

4 0
3 years ago
Please help need to turn in almost ! Pic below<br> Thank you so much:)
11111nata11111 [884]

Answer:

x = 90-73

= 17°

.................

4 0
3 years ago
Read 2 more answers
Evaluate 4x power of 3 +4x when x=3
viva [34]

\text{Hey there!}

\text{Evaluate:\ }\bf{4x^3+4x}\text{ if x = 3}

\text{If we know what the x-value is then replace the x with 3}

\bf{4(3)^3+4(3)}

\bf{4(3)^3+12}

\text{4 = 4}

\bf{3^3=27}

\text{4(3) = 12}

\text{4(27) + 12}

\text{4(12)=108}

\text{108 + 12 = 120}

\boxed{\boxed{\text{Answer: 120}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

4 0
3 years ago
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