Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
The ends of the graph will extend in opposite directions.
Hope this helped!
Answer:
-7
Step-by-step explanation:
Given
Required
The first difference
To do this, we simply calculate the difference between the consecutive y-values.
i.e.
So, we have:
<em>Hence, the first differences are -7 (all through)</em>
I believe the slope of the line is 1/3
Answer: $23.10
Step-by-step explanation:
18/3 = 6
3.85 x 6 = $23.10
