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2 years ago

Find the value of X. Write your

Mathematics

1 answer:

ivolga24 [154]2 years ago

7 0

Sin45°=p/h
1/√2=x/4√2
x√2=4√2
x=4

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Is −4[3(x−7)] and 6(14−2x) equiviant

Paraphin [41]

Answer:

Yes.

Step-by-step explanation:

Set the equations equal to each other to determine their equality.

-4[3(x - 7)] = 6(14 - 2x)

Distribute the 3 and the 6 into their respective parenthesis.

-4[3x - 21] = 84 - 12x

Distribute the -4 into the brackets.

-12x + 84

Rearrange the equations.

84 - 12x = 84 - 12x

Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.

4 0

2 years ago

Determine the value of x and y in the following systems of equations5x-2y=4 ; -2x+y=2.

V125BC [204]

Answer:(x,y)=(8,18)

Step-by-step explanation:

Given

5x-2y=4-------1

Second Equation

-2x+y=2-----2

Now multiply equation 2 by 2 and it to equation 1

5x-4x+0=8

x=8

substitute it in equation 1

$5\times 8-2\times y=4$

36=2y

y=18

Therefore

(x,y)=(8,18)

7 0

2 years ago

What graph is a function of x

Nookie1986 [14]

Show me the picture for I can help u

3 0

3 years ago

Can someone help me with this

Art [367]

Ans57 , 58 , 59

Step-by-step explanation:

5 0

1 year ago

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

8 0

3 years ago