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Archy [21]
3 years ago
11

What is the half-life of a radioactive isotope that decreases to one fourth its original amount in 18 months

Physics
1 answer:
just olya [345]3 years ago
7 0
9 months, because half of 18 is 9
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A 3.0-kg block is on a horizontal surface. The block is at rest when, at t = 0, a force (magnitude P = 12 N) acting parallel to
GarryVolchara [31]

Explanation:

It is given that,

Mass of the block, m = 3 kg

Initially, the block is at rest, u = 0

Force acting on the block, P = 12 N

The coefficient of kinetic friction between the block and the surface is, \mu_k=0.2

We need to find the rate is the force P doing work on the block at t = 2.0 s. The rate at which work is done is called the power. Let is equal to P'

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f=0.2\times 3\ kg\times 9.8\ m/s^2=5.88\ N

So, the net force acting on the block, F = P - f

F=12-5.88=6.12\ N

Let a is the acceleration of the block, a=\dfrac{F}{m}

a=\dfrac{6.12}{3}=2.04\ m/s^2

Let v is the velocity of the block after 2 seconds. So,

v=u+at

v=0+2.04\times 2

v = 4.08 m/s

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P'=12\ N\times 4.08\ m/s=48.96\ Watts

So, the force P is doing work on the block at the rate of 48.96 watts.

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3 years ago
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Answer:

The diagonal or the inclined lines shows the changes in terms of temperature, and the horizontal lines shows the changing of phases.

Explanation:

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pychu [463]
Using geometrical arguments, we can see that the angle of the inclined plane \theta is equal to the angle between Fg and the perpendicular force.

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<span>C) F=mg cosΘ </span>
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True or false
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If im not mistaken it is true
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