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Ivahew [28]
3 years ago
6

True or false

Physics
1 answer:
ElenaW [278]3 years ago
4 0
If im not mistaken it is true
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The fraction of nonreflected radiation that is transmitted through a 5-mm thickness of a transparent material is 0.95. if the th
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How much force is needed to slow down a 15 kg car traveling at 60 m/s to 15 m/s in 10 seconds?​
goldfiish [28.3K]

Answer:

The force needed to slow down the car is, F = 67.5 N

Explanation:

Given data,

The mass of the car, m = 15 kg

The initial velocity of the car, V = 60 m/s

The final velocity of the car, v = 15 m/s

The time period of deceleration, t = 10 s

The difference in the momentum of the car is,

                                     mV - mv = 15(60 - 15)

                                                    = 675 kg m/s

The rate of change in momentum of the car gives the force acting on it.

                                    F = (mV - mu) / t

Substituting the values,

                                   F = 675 / 10

                                      = 67.5 N

Hence, the force needed to slow down the car is, F = 67.5 N

3 0
3 years ago
Why do people make this to the seashore?
Nadya [2.5K]

Answer:

Protecting the Seashore

Seashore Conservation Code

When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.

Pollution Problems

Seas and seashores are under continual threat from pollution. Here are some examples:-

oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.

Sewage and litter also upsets seashore ecosystem, making them unsightly and perhaps contaminated. Some litter can be dangerous to wildlife.

Toxic chemicals and radioactive waste - a cocktail of toxic chemicals have found their way into the sea over the years, affecting both marine and human life. For many years potentially deadly radioactive waste from nuclear power stations and other sources was disposed of in the sea, and beaches have been contaminated by accidental leakages from nuclear power stations.

Explanation:

5 0
3 years ago
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A horizontal pipe 18.0 cm in diameter has a smooth reduction to a pipe 9.00 cm in diameter. If the pressure of the water in the
Rzqust [24]

Answer:

The rate of flow of water is 71.28 kg/s

Solution:

As per the question:

Diameter, d = 18.0 cm

Diameter, d' = 9.0 cm

Pressure in larger pipe, P = 9.40\times 10^{4}\ Pa

Pressure in the smaller pipe, P' = 2.80\times 10^{4}\ Pa

Now,

To calculate the rate of flow of water:

We know that:

Av = A'v'

where

A = Cross sectional area of larger pipe

A' = Cross sectional area of larger pipe

v = velocity of water in larger pipe

v' = velocity of water in larger pipe

Thus

\pi \frac{d^{2}}{4}v = \pi \frac{d'^{2}}{4}v'

18^{2}v = 9^v'

v' = 4v

Now,

By using Bernoulli's eqn:

P + \frac{1}{2}\rho v^{2} + \rho gh = P' + \frac{1}{2}\rho v'^{2} + \rho gh'

where

h = h'

\rho = 10^{3}\ kg/m^{3}

9.40\times 10^{4} + \frac{1}{2}\rho v^{2} = 2.80\times 10^{4} + \frac{1}{2}\rho (4v)^{2}

6.6\times 10^{4}  = \frac{1}{2}\rho 15v^{2}

v = \sqrt{\frac{2\times 6.6\times 10^{4}}{15\times 10^{3}}} = 8.8\ m/s

Now, the rate of flow is given by:

\frac{dm}{dt} = \frac{d}{dt}\rho Al = \rho Av

\frac{dm}{dt} = 10^{3}\times \pi (\frac{18}{2}\times 10^{- 2})^{2}\times 8.8 = 71.28\ kg/s

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3 years ago
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People who have color vision deficiency typically lack one or more of the three cones that are sensitive to a particular wavelength.
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