Answer:1.008 ×10^-14/rJ
Where r is the distance from.which the charge was moved through.
Explanation:
From coloumbs law
Work done =KQq/r
Where K=9×10^9
Q=7×10^-6C
q=e=1.6×10^-19C
Micro is 10^-6
W=9×10^9×7×10^-6×1.6×10^-19/r=100.8×10^-16/r=1.008×10^-14/rJ
r represent the distance through which the force was used to moved the charge through.
Answer:
50 m
Explanation:
Acceleration= force/mass
3000/3000=1m/s^-2
Applying equation of motion:
V^2=U^2+2as; V is final velocity, u is initial velocity, a is acceleration and s is the distance covered.
0=10^2 -2*1s;
Solve for s
Answer:
2.5m/s^2
Explanation:
Step one:
given
distance = 20meters
time = 2 seconds
initial velocity u= 0m/s
let us solve for the final velocity
velocity = distance/time
velocity= 20/2
velocity= 10m/s
divide both sides by 40
