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Degger [83]
3 years ago
14

PLEASE HELP ASAP URGENT!!!!!

Physics
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

B

i am not fully sure but i believe its the most accurate its either A or B

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Is the force of gravity stronger on a piece of crumpled paper or a normal piece of flat paper?
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Yes, because a crumpled piece of paper has more center mass, allowing it to fall faster.
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Gravity is dependent on which of the two factors?
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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 12 N. The carriage has pote
Ivanshal [37]

The gravitational potential energy is 252 J

Explanation:

The Gravitational Potential Energy (GPE) of an object is given by

GPE=Wh

where

W is the weight of the object

h is the height of the object above the ground

For the carriage and the baby in this problem, we have

W = 21 N is their weight

h = 21 m is their height above the ground

Substituting,

GPE=(12)(21)=252 J

Learn more about gravitational potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

4 0
3 years ago
Please help. I don’t understand this
skad [1K]

The short answer is that the displacement is equal tothe area under the curve in the velocity-time graph. The region under the curve in the first 4.0 s is a triangle with height 10.0 m/s and length 4.0 s, so its area - and hence the displacement - is

1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

According to the plot, with ∆<em>t</em> = 4.0 s, we have <em>v</em> (initial) = 0 and <em>v</em> (final) = 10.0 m/s, so

∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

∆<em>x</em> = 20.00 m

5 0
2 years ago
A wave is produced from a vibrating string on a violin. Two observers are standing 20 m and 40 m away from the musician. The obs
max2010maxim [7]

Well the one that is closer can see and hear more

3 0
3 years ago
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