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Lady_Fox [76]
3 years ago
12

A cat chases a mouse until the cat gets tired. A graph of the cat's velocity over time is shown below. Velocity 8+ 6+ 9+ 2 Time

is) 2 3 What is the cat's average acceleration from 12 to 24 seconds? Answer using two digrii cont ligures​
Physics
2 answers:
iragen [17]3 years ago
8 0

Answer:

-0.67

Explanation:

khan academy

(final velocity minus initial velocity) divided by time

defon3 years ago
6 0

Answer:

-0.67

Explanation:

khan academy

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s
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Answer:

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe       ..... (1)

T Cosθ = mg     .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}

tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}

tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}

tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}

As θ is very small, so tanθ and Sinθ is equal to θ.

\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

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