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2 years ago

What is the area of the parallelogram?

Mathematics

2 answers:

Molodets [167]2 years ago

8 0

A=bh which means 900=50x18

aleksley [76]2 years ago

4 0

For area- bxh which will give the answer. hope this helps

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Which of the following is equivalent to tan 5pie/6?

nataly862011 [7]

Answer: should be -1/ sqrt of 3. If it asks to rationalize it could be -sqrt of 3/3

Step-by-step explanation:

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2 years ago

Find the value of g(-1)

Anna11 [10]

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g(-1) = -3

Step-by-step explanation:

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2 years ago

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1 year ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

Answer- Length of the curve of intersection is 13.5191 sq.units

Solution-

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

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3 years ago

Which of the following does the situation below best describe?

mestny [16]

The answer to the question is c

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2 years ago