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3 years ago

15

A wave travels at a constant speed. How does the frequency change if the wavelength is reduced by a factor of 4

2 answers:

Andre45 [30]3 years ago

8 0

Answer: The frequency increases by a factor of 4.

Explanation:

sweet-ann [11.9K]3 years ago

4 0

The product of (wavelength) x (frequency) is always the same number ... the wave's speed.

So if the wavelength is somehow reduced to 1/4 its original length, the <em>frequency is immediately multiplied by 4</em> . That's the only way their product can remain the same.

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What velocity must a 1210 kg car have in order to have the same momentum as a pickup truck

Mariulka [41]

Answer: 46.5 m/s

Explanation:

Momentum = mass(m) × velocity (v)

momentum of car = momentum of truck

1210 × v = 2250 × 25

v = 46.5 m/s

6 0

3 years ago

How fast would the International Space Station (ISS) have to travel to maintain a circular orbit a distance of 1400 km above the

professor190 [17]

Answer:

The International Space Station move at 7.22 km/s.

Explanation:

Orbital speed of satellite is given by $v=\sqrt{\frac{GM}{r}}$ , where G is gravitational constant, M is mass of Earth and r is the distance to satellite from centre of Earth.

r = R + h = 6350 + 1400 = 7750 km = 7.75 x 10⁶ m

G = 6.673 x 10⁻¹¹ Nm²/kg²

M = 5.98 x 10²⁴ kg

Substituting

$v=\sqrt{\frac{6.673\times 10^{-11}\times 5.98\times 10^{24}}{7.75\times 10^6}}=7223.86m/s=7.22km/s$

The International Space Station move at 7.22 km/s.

4 0

3 years ago

We want to construct a solenoid with a resistance of 4.30 Ω and generate a magnetic field of 3.70 × 10−2 T at its center when ap

marshall27 [118]

Answer with Explanation:

We are given that

Resistance of solenoid,R=4.3 ohm

Magnetic field,B= $3.7\times 10^{-2} T$

Current,I=4.6 A

Diameter of wire,d=0.5 mm= $0.5\times 10^{-3} m$

Radius of wire,r= $\frac{d}{2}=\frac{0.5\times 10^{-3}}{2}=0.25\times 10^{-3} m$

$1mm=10^{-3} m$

Radius of solenoid,r'=1 cm= $1\times 10^{-2} m$

$1 cm=10^{-2} m$

Resistivity of copper, $\rho=1.68\times 10^{-8}\Omega m$

We know that

$R=\frac{\rho l}{A}$

Where $A=\pi r^2$

Using the formula

$4.3=\frac{1.68\times 10^{-8}\times l}{\pi(0.25\times 10^{-3})^2}$

$l=\frac{4.3\times \pi(0.25\times 10^{-3})^2}{1.68\times 10^{-8}}=50.23 m$

Number of turns of wire= $\frac{l}{2\pi r'}$

Number of turns of wire= $\frac{50.26}{2\pi(1\times 10^{-2}}=800$

Hence, the number of turns of the solenoid,N=799

Magnetic field in solenoid,B= $\mu_0 nI$

$3.7\times 10^{-2}=4\pi\times 10^{-7} n\times 4.6$

$n=\frac{3.7\times 10^{-2}}{4\times 3.14\times 10^{-7}\times 4.6}$

$n=6404 turns/m$

$n=\frac{N}{L}$

$L=\frac{N}{n}$

$L=\frac{799}{6404}$

$L=0.125 m=0.125\times 100=12.5 cm$

Length of solenoid=12.5 cm

1m=100 cm

8 0

4 years ago

5. A current of 3.00 A flows through a resistor when it is connected

viktelen [127]

I think it is D
Hope my answer help you?

7 0

3 years ago

A wagon has a mass of 100 grams and an

olga2289 [7]

Answer:

Net force on the wagon is 200 N

Explanation:

As we know by Newton's II law that net force on the system of mass is given as product of mass and acceleration

Here we know that

mass = 100 kg

a = 2 m/s/s

now we have

$F = ma$

$F = (100)(2)$

$F = 200 N$

3 0

3 years ago