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alekssr [168]
4 years ago
13

Which of the following best explains how the Ptolemy’s (geocentric) and Copernicus’s (heliocentric) models of the solar system d

iffered? (DOK 2)
A.
Ptolemy’s views of the solar system were rejected, but Copernicus’ views were widely accepted.

B.
Ptolemy did not have an explanation for why planets would seem to move backward, but Copernicus did.

C.
Ptolemy believed everything revolved around the Earth,, while Copernicus believed everything revolved around the Sun.



D.
Ptolemy believed everything revolved around the Sun, while Copernicus believed everything revolved around the Earth.
Physics
1 answer:
TiliK225 [7]4 years ago
7 0

Answer:

The correct answer is c

Explanation:

In these two different models of movement of the planets

Ptolemy raises the Earth as the center of the solar system

In the Copernicus system, it poses the Sun as the center of the solar system.

Copernicu's system was accepted for giving a simpler and more complete explanation of the problem

The correct answer is c

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The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the
frozen [14]

Answer:

\theta = 49.81^0

Explanation:

Given that:

\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})

where;

v = \frac{\omega d}{2}\\\\v =  \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77

Again:

\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0

6 0
3 years ago
Calculate the work done by a 47N force pushing a pencil against a force of 23 N
stira [4]
I believe the answer would be 24N
Explanation: Because the forces are going against each other, in order to calculate the work done we need to subtract them. 47-23=24
8 0
2 years ago
Sirius A is 8.6 light-years from Earth. What is this distance in kilometers? What is this distance in feet?
Jlenok [28]

Answer:

a. 8.136 × 10¹³ km b. 2.669 × 10¹⁹ feet

Explanation:

a. What is this distance in kilometers?

Since Sirius A is 8.6 light years away from Earth and one light year = distance travelled by light in a year = 3 × 10⁸ m/ s × 365 days/year × 24 hr/day × 3600 s/hr = 9.4608 × 10¹⁵ m = 9.4608 × 10¹² km.

Then 8.6 light years = 8.6 × 1 light year

= 8.6 × 9.4608 × 10¹² km

= 81.363 × 10¹² km

= 8.1363 × 10¹³ km

≅ 8.136 × 10¹³ km

b.  What is this distance in feet?

Since 1 meter = 3.28 feet,

8.6 light years = 8.1363 × 10¹² km

= 8136.3 × 10¹⁵ m

= 8136.3 × 10¹⁵ × 1 m

= 8136.3 × 10¹⁵ × 3.28 feet

= 26687.1  × 10¹⁵ feet

= 2.66871 × 10¹⁹ feet

≅ 2.669 × 10¹⁹ feet

3 0
3 years ago
An electric circuit has a 200 22 resistor and a current of 5 A. What is its voltage?
Wittaler [7]

Answer:

ccccccc. ccccccc ccc ccccccc c

8 0
3 years ago
A cubic box of volume 5.1 x 10 -2m3 is
I am Lyosha [343]

Answer:

21544 N

Explanation:

Let the atmospheric pressure be 101325 Pa

The side length of the cubic box:

V = d^3 = 0.051m^3

d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m

The area of the cubic box:

A = d^2 = 0.371^2 = 0.1375 m^2

20 C = 20 + 273 = 293 K

180 C = 180 + 273 = 453 K

As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

\frac{P_1}{T_1} = \frac{P_2}{T_2}

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

P_2 = P_1\frac{T_2}{T_1} = 101325\frac{453}{293} = 156656 Pa

The net force on each side of the box it its pressure times side area

F = P_2A = 156656 * 0.1375 = 21544 N

8 0
3 years ago
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