Answer:

Explanation:
Given that:

If we let the piece of the close lose contact at ∠θ;
Then ; from force balance;
we have:

where;

Again:

I believe the answer would be 24N
Explanation: Because the forces are going against each other, in order to calculate the work done we need to subtract them. 47-23=24
Answer:
a. 8.136 × 10¹³ km b. 2.669 × 10¹⁹ feet
Explanation:
a. What is this distance in kilometers?
Since Sirius A is 8.6 light years away from Earth and one light year = distance travelled by light in a year = 3 × 10⁸ m/ s × 365 days/year × 24 hr/day × 3600 s/hr = 9.4608 × 10¹⁵ m = 9.4608 × 10¹² km.
Then 8.6 light years = 8.6 × 1 light year
= 8.6 × 9.4608 × 10¹² km
= 81.363 × 10¹² km
= 8.1363 × 10¹³ km
≅ 8.136 × 10¹³ km
b. What is this distance in feet?
Since 1 meter = 3.28 feet,
8.6 light years = 8.1363 × 10¹² km
= 8136.3 × 10¹⁵ m
= 8136.3 × 10¹⁵ × 1 m
= 8136.3 × 10¹⁵ × 3.28 feet
= 26687.1 × 10¹⁵ feet
= 2.66871 × 10¹⁹ feet
≅ 2.669 × 10¹⁹ feet
Answer:
ccccccc. ccccccc ccc ccccccc c
Answer:
21544 N
Explanation:
Let the atmospheric pressure be 101325 Pa
The side length of the cubic box:

![d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%5B3%5D%7BV%7D%20%3D%20%5Csqrt%5B3%5D%7B0.051%7D%20%3D%200.371%20m)
The area of the cubic box:

20 C = 20 + 273 = 293 K
180 C = 180 + 273 = 453 K
As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

The net force on each side of the box it its pressure times side area
