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Oxana [17]
3 years ago
10

Which of these energy transformations is not part of how a nuclear power plant

Physics
1 answer:
frutty [35]3 years ago
7 0
I think the second one
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A solid block, with a mass of 0.15kg, on a frictionless surface is pushed directly onto a horizontal spring, with a spring const
iren [92.7K]

Answer:

16.1 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by

U=\frac{1}{2}kx^2

where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to

K=\frac{1}{2}mv^2

where m = 0.15 kg is the mass of the block and v is its speed.

Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:

\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(316 N/m)(0.35 m)^2}{0.15 kg}}=16.1 m/s

4 0
3 years ago
Why is pseudoscience bad?
Dmitrij [34]

Answer:

Because psuedoscience is a collection of beliefs or practices mistakenly regarded as being based on scientific method.

And it is most of the time false

Explanation:

5 0
2 years ago
What is noncontact force
Musya8 [376]

Answer:

A non-contact force is a force which acts on an object without coming physically in contact with it.

Explanation:

For example:

<em>Gravitational force.</em>

<em>Magnetic force.</em>

<em>Electrostatics.</em>

<em>Nuclear force.</em>

6 0
3 years ago
Read 2 more answers
What is the difference between branch current and loop current..?..(plz...don't say that the current that flows in branches is t
ki77a [65]
The current flowing into the branches, or branch current, is divided according to the resistance in the branch that it is going into. Loop current remains the same.
4 0
3 years ago
A tension force of 175 N inclined at 20.0° above the horizontal is used to pull a 40.0 - kg packing crate a distance of 6.00 m o
Murljashka [212]

Answer:

(a) Work done by the tension force is 987 J

(b) Coefficient of kinetic friction between the crate and surface is 0.495

Explanation:

(a)

Work done by any force F in moving an object by a distance d making an angle \Theta with the direction of force  is given by

W=Fd\cos (\Theta )

W=175 \times 6 \times  \cos (20 )J=987J

Thus work done by the tension force is 987 J

(b)

Normal force on the crate is given by

N= mg-F\sin \Theta  =(40\times 9.8-175\times \sin 20)Newton

=>N=332 Newtons

Since crate is moving with constant speed . Therefore using Newtons second law .

Fcos(\Theta ) -\mu_k N=0

Where \mu_k=coefficient of kinetic friction

\therefore \mu_k=\frac{F\cos (\Theta )}{N}

=>\mu_k=\frac{175\times \cos 20}{332}

=>\mu _k= 0.495

Thus coefficient of kinetic friction between the crate and surface is 0.495

4 0
3 years ago
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