3 years ago

PLEASE HELP!!!!!!!!!!!!!!

Mathematics

1 answer:

sveta [45]3 years ago

5 0

I graphed the problem and I got this. I hope this helps

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If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4? a. 3.75 b. 1.67 c. 0.1 d. 7.5 Please select the best

REY [17]

Because y varies inversely as x, therefore
$y= \frac{k}{x}$
where k = constant.

When x = 6, y = 2.5. Ther efore
$\frac{k}{6} = 2.5$
Cross multiply.
k = 6 x 2.5 = 15

The equation is
$y = \frac{15}{x}$

When x = 4, obtain
$y = \frac{15}{4}= 3.75$

Answer: a. 3.75

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Work Shown:

I'm assuming you meant to write 4p^3+8p^2+3p+6

If so, then we would have these steps

4p^3+8p^2+3p+6

(4p^3+8p^2)+(3p+6)

4p^2(p+2)+3(p+2)

(4p^2+3)(p+2)

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Step-by-step explanation:

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